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Revision difference : anti-isomorphism
Version 2 Version 1
Let $R$ and $S$ be rings. A function $f: R \longrightarrow S$ is said to be an ${\it anti-isomorphism}$ if it is an A function $f: R->S$ is said to be an ${\it anti-isomorphism}$ if it is an
isomorphism of the additive groups of $R$ and $S$ and isomorphism of the additive groups of $R$ and $S$ and
$f(r_{1}r_{2}) = f(r_{2}r_{1})$ for all $r_{1}, r_{2} \in R$. $f(r_{1}r_{2}) = f(r_{2}r_{1})$ for all $r_{1}, r_{2} \in R$.
If $R=S$, then $f$ is called an ${\it anti-endomorphism}$. If $R=S$, then $f$ is called an ${\it anti-endomorphism}$.