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| In a triangle, having the sides $a$, $b$ and $c$ opposite to the angles $\alpha$, $\beta$ and $\gamma$ respectively the following equations hold: |
In a triangle, having the sides $a$, $b$ and $c$ opposite to the angles $\alpha$, $\beta$ and $\gamma$ respectively the following equations hold: |
| $$(a+b)\sin \frac{\gamma}{2}=c\cos\left(\frac{\alpha -\beta}{2}\right)$$ |
$$(a+b)\sin \frac{\gamma}{2}=c\cos\left(\frac{\alpha -\beta}{2}\right)$$ |
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| $$(a-b)\cos\frac{\gamma}{2}=c\sin\left(\frac{\alpha -\beta}{2}\right).$$ |
$$(a-b)\cos\frac{\gamma}{2}=c\sin\left(\frac{\alpha -\beta}{2}\right).$$ |
