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Let $F: \mathbb{R}\to \mathbb{R}$. Then $F$ is a \emph{distribution function} if Let $F: \mathbb{R}\to \mathbb{R}$. Then $F$ is a \emph{distribution function} if
\begin{enumerate} \begin{enumerate}
\item \item
$F$ is nondecreasing, $F$ is nondecreasing,
\item \item
$F$ is continuous from the right, $F$ is continuous from the right,
\item \item
$\lim_{x \rightarrow -\infty} F(x) = 0$, and $\lim_{x \rightarrow \infty} F(x) = 1$. $\lim_{x \rightarrow -\infty} F(x) = 0$, and $\lim_{x \rightarrow \infty} F(x) = 1$.
\end{enumerate} \end{enumerate}
As an example, suppose that $\Omega = \mathbb{R}$ and that $\mathcal{B}$ As an example, suppose that $\Omega = \mathbb{R}$ and that $\mathcal{B}$
is the $\sigma$-algebra of Borel subsets of $\mathbb{R}$. is the $\sigma$-algebra of Borel subsets of $\mathbb{R}$.
Let $P$ be a probability measure on $(\Omega, \mathcal{B})$. Let $P$ be a probability measure on $(\Omega, \mathcal{B})$.
Define $F$ by Define $F$ by
$$ $$
F(x) = P((-\infty, x]). F(x) = P((-\infty, x]).
$$ $$
This particular $F$ is called the \emph{distribution function} of $P$. It is This particular $F$ is called the \emph{distribution function} of $P$. It is
easy to verify that 1,2, and 3 hold for this $F$. easy to verify that 1,2, and 3 hold for this $F$.
In fact, every distribution function is the distribution function of some In fact, every distribution function is the distribution function of some
probability measure on the Borel subsets of $\mathbb{R}$. To see this, probability measure on the Borel subsets of $\mathbb{R}$. To see this,
suppose that $F$ is a distribution function. We can define $P$ on a single half-open suppose that $F$ is a distribution function. We can define $P$ on a single half-open
interval by interval by
$$ $$
P((a,b]) = F(b) - F(a) P((a,b]) = F(b) - F(a)
$$ $$
and extend $P$ to unions of disjoint intervals by and extend $P$ to unions of disjoint intervals by
$$ $$
P( \cup_{i=1}^\infty (a_i, b_i])= \sum_{i=1}^\infty P((a_i, b_i]). P( \cup_{i=1}^\infty (a_i, b_i])= \sum_{i=1}^\infty P((a_i, b_i]).
$$ $$
and then further extend $P$ to all the Borel subsets of $\mathbb{R}$. and then further extend $P$ to all the Borel subsets of $\mathbb{R}$.
It is clear that the distribution function of $P$ is $F$. It is clear that the distribution function of $P$ is $F$.
\subsection{Random Variables} \subsection{Random Variables}
Suppose that $(\Omega, \mathcal{B}, P)$ is a probability space and Suppose that $(\Omega, \mathcal{B}, P)$ is a probability space and
$X: \Omega \to \mathbb{R}$ is a random variable. Then there is an $X: \Omega \to \mathbb{R}$ is a random variable. Then there is an
\emph{induced} probability measure $P_X$ on $\mathbb{R}$ defined as \emph{induced} probability measure $P_X$ on $\mathbb{R}$ defined as
follows: \\ follows: \\
$$ $$
P_X(E) = P(X^{-1}(E)) P_X(E) = P(X^{-1}(E))
$$ $$
for every Borel subset $E$ of $\mathbb{R}$. $P_X$ is called the for every Borel subset $E$ of $\mathbb{R}$. $P_X$ is called the
\emph{distribution} of $X$. The \emph{distribution function} \emph{distribution} of $X$. The \emph{distribution function}
of $X$ is of $X$ is
$$ $$
F_X(x) = P(\omega | X(\omega) \leq x). F_X(x) = P(\omega | X(\omega) \leq x).
$$ $$
Claim: $F_X$ = the distribution function of $P_X$. Claim: $F_X$ = the distribution function of $P_X$.
\begin{eqnarray*} \begin{eqnarray*}
F_X(x) &=& P(\omega | X(\omega) \leq x) \\ F_X(x) &=& P(\omega | X(\omega) \leq x) \\
&=& P(X^{-1}((-\infty, x]) \\ &=& P(X^{-1}((-\infty, x]) \\
&=& P_X((-\infty, x]) \\ &=& P_X((-\infty, x]) \\
&=& F(x). &=& F(x).
\end{eqnarray*} \end{eqnarray*}
\subsection{Density Functions} \subsection{Density Functions}
Suppose that $f: \mathbb{R} \to \mathbb{R}$ is a nonnegative function Suppose that $f: \mathbb{R} \to \mathbb{R}$ is a nonnegative function
such that such that
$$ $$
\int_{-\infty}^\infty f(t)dt=1. \int_{-\infty}^\infty =1.
$$ $$
Then one can define $F: \mathbb{R} \to \mathbb{R}$ by Then one can define $F: \mathbb{R} \to \mathbb{R}$ by
$$ $$
F(x) = \int_{-\infty}^x f(t)dt. F(x) = \int_{-\infty}^x f(t)dt.
$$ $$
Then it is clear that $F$ satisfies the conditions 1,2,and 3 so $F$ Then it is clear that $F$ satisfies the conditions 1,2,and 3 so $F$
is a distribution function. The function $f$ is called a density function is a distribution function. The function $f$ is called a density function
for the distribution $F$. for the distribution $F$.
If $X$ is a discrete random variable with density function $f$ and distribution If $X$ is a discrete random variable with density function $f$ and distribution
function $F$ then function $F$ then
$$F(x)=\sum_{x_j\leq x} f(x_j).$$ $$F(x)=\sum_{x_j\leq x} f(x_j).$$