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Revision difference : norm and trace of algebraic number
Version current Version 11
\begin{thmplain} \begin{thmplain}
\, Let $K$ be an algebraic number field and $\alpha$ an element of $K$.\, The norm $\mbox{N}(\alpha)$ and the trace $\mbox{S}(\alpha)$ of $\alpha$ in the field extension $K/\mathbb{Q}$ both are rational numbers and especially rational integers in the case $\alpha$ is an algebraic integer.\, If $\beta$ is another element of $K$, then \, Let $K$ be an algebraic number field and $\alpha$ an element of $K$.\, The norm $\mbox{N}(\alpha)$ and the trace $\mbox{S}(\alpha)$ of $\alpha$ in the field extension $K/\mathbb{Q}$ both are rational numbers and especially rational integers in the case $\alpha$ is an algebraic integer.\, If $\beta$ is another element of $K$, then
\begin{align} \begin{align}
\mbox{N}(\alpha\beta) \;=\; \mbox{N}(\alpha)\mbox{N}(\beta), \quad \mbox{N}(\alpha\beta) = \mbox{N}(\alpha)\mbox{N}(\beta), \quad
\mbox{S}(\alpha\!+\!\beta) \;=\; \mbox{S}(\alpha)\!+\!\mbox{S}(\beta), \mbox{S}(\alpha+\beta) = \mbox{S}(\alpha)+\mbox{S}(\beta),
\end{align} \end{align}
i.e. the norm is multiplicative and the trace additive.\, If\, i.e. the norm is multiplicative and the trace additive.\, If\,
$[K\!:\!\mathbb{Q}] = n$\, and\, $a\in\mathbb{Q}$, then $[K\!:\!\mathbb{Q}] = n$\, and\, $a\in\mathbb{Q}$, then
$$\mbox{N}(a) = a^n, \quad \mbox{S}(a) = na.$$ $$\mbox{N}(a) = a^n, \quad \mbox{S}(a) = na.$$
\end{thmplain} \end{thmplain}
\textbf{Remarks} \textbf{Remarks}
1.\, The notions norm and trace were originally introduced in German \PMlinkescapetext{language} as ``die Norm'' and ``die Spur''.\, Therefore in German and many other literature the symbol of trace is S, Sp or sp.\, Nowadays the symbols T and Tr are common. 1.\, The notions norm and trace were originally introduced in German \PMlinkescapetext{language} as ``die Norm'' and ``die Spur''.\, Therefore in German and many other literature the symbol of trace is S, Sp or sp.\, Nowadays the symbols T and Tr are common.
2.\, The norm and trace of an algebraic number $\alpha$ in the field extension\, $\mathbb{Q}(\alpha)/\mathbb{Q}$,\, i.e. the product and sum of all algebraic conjugates of $\alpha$, are called the {\em absolute norm} and the {\em absolute trace} of $\alpha$.\, Formulae like (1) concerning the absolute norms and traces are not sensible.\, 2.\, The norm and trace of an algebraic number $\alpha$ in the field extension\, $\mathbb{Q}(\alpha)/\mathbb{Q}$,\, i.e. the product and sum of all algebraic conjugates of $\alpha$, are called the {\em absolute norm} and the {\em absolute trace} of $\alpha$.\, Formulae like (1) concerning the absolute norms and traces are not sensible.\,
\begin{thmplain} \begin{thmplain}
\, An algebraic integer $\varepsilon$ is a unit if and only if \, An algebraic integer $\varepsilon$ is a unit if and only if
$$\mbox{N}(\varepsilon) \;=\; \pm 1,$$ $$\mbox{N}(\varepsilon) = \pm 1,$$
i.e. iff the absolute norm of $\varepsilon$ is a rational unit.\, Thus \PMlinkescapetext{the constant term} in the minimal polynomial of an algebraic unit is always \,$\pm 1$. i.e. iff the absolute norm of $\varepsilon$ is a rational unit.\, Thus \PMlinkescapetext{the constant term} in the minimal polynomial of an algebraic unit is always \,$\pm 1$.
\end{thmplain} \end{thmplain}
\textbf{Example.}\, The minimal polynomial of the number $2\!+\!\sqrt{3}$, which is the fundamental unit of the quadratic field $\mathbb{Q}(\sqrt{3})$, is \,$x^2\!-\!4x\!+\!1$. \textbf{Example.}\, The minimal polynomial of the number $2+\sqrt{3}$, which is the fundamental unit of the quadratic field $\mathbb{Q}(\sqrt{3})$, is \,$x^2-4x+1$.