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Revision difference : Euclidean valuation
Version 3 Version 2
Let $D$ be an integral domain. An Euclidean valuation is a function from non-zero elements to the non-negative integers Let $D$ be an integral domain. An Euclidean valuation is a function from non-zero elements to the non-negative integers
$$\nu :D-\{0\}\to\Z^+\cup\{0\}$$ $$\nu :D-\{0\}\to\Z^+\cup\{0\}$$
such that such that
\begin{itemize} \begin{itemize}
\item For any $a,b\in D$, $b\neq 0$, there exist $q,r\in D$ such that $a=bq+r$ with $\nu(r)<\nu(b)$ or $r=0$. \item For any $a,b\in D$, $b\neq 0$, there exist $q,r\in D$ such that $a=bq+r$ with $\nu(r)<\nu(b)$ or $r=0$.
\item For any $a,b\in D$ both non-zero, $\nu(a)\leq\nu(ab)$. \item For any $a,b\in D$ both non-zero, $\nu(a)\leq\nu(ab)$.
\end{itemize} \end{itemize}
Euclidean valuations are important because they let us define greatest common divisors and use Euclid's algorithm. Some facts about Euclidean valuations: Euclidean valuations are important because they let us define greatest common divisors and use Euclid's algorithm. Some facts about Euclidean valuations:
\begin{itemize} \begin{itemize}
\item The value $\nu(1)$ is minimal. That is, $\nu(1)\leq\nu(a)$ for any nonzero element of $D$. \item The value $\nu(1)$ is minimal. That is, $\nu(1)\leq\nu(a)$ for any nonzero element of $D$.
\item $u\in D$ is an unit if an only if $\nu(u)=\nu(1)$. \item $u\in D$ is an unit if an only if $\nu(u)=\nu(1)$.
\end{itemize} \end{itemize}