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Revision difference : state
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A \textbf{state} $\Psi$ on a $C^*$-algebra $A$ is a positive linear functional A \defn{state} $\Psi$ on a $C^*$-algebra $A$ is a positive linear functional
$\Psi\colon A \to \Cset$, $\Psi(a^*a) \geq 0$ for all $a \in A$, with unit norm. $\Psi : A \to \Cset$, $\Psi(a^*a) \geq 0$ for all $a \in A$, with unit norm.
The norm of a positive linear functional is defined by The norm of a positive linear functional is defined by
\begin{equation} \begin{equation}
\norm{\Psi} = \sup_{a \in A}\{|\Psi(a)| : \norm{a}\leq 1\}. ||\Psi|| = \sup_{a \in A}\{|\Psi(a)| : ||a||\leq 1\}.
\end{equation} \end{equation}
For a unital $C^*$-algebra, $\norm{\Psi} = \Psi(\identity)$. For a unital $C^*$-algebra, $||\Psi|| = \Psi(\identity)$.
The space of states is a convex set. The space of states is a convex set.
Let $\Psi_1$ and $\Psi_2$ be states, then the convex combination Let $\Psi_1$ and $\Psi_2$ be states, then the convex combination
\begin{equation} \begin{equation}
\lambda\Psi_1+(1-\lambda)\Psi_2, \quad \lambda \in [0,1], \lambda\Psi_1+(1-\lambda)\Psi_2, \quad \lambda \in [0,1],
\end{equation} \end{equation}
is also a state. is also a state.
A state is \defn{pure} if it is not a convex combination of two other states.
A state is \textbf{pure} if it is not a convex combination of two other states.
Pure states are the extreme points of the convex set of states. Pure states are the extreme points of the convex set of states.
A pure state on a commutative $C^*$-algebra is equivalent to a character. A pure state on a commutative $C^*$-algebra is equivalent to a character.
A state is called a \defn{tracial state} if it is also a trace.
A state is called a \textbf{tracial state} if it is also a trace.
When a $C^*$-algebra is represented on a Hilbert space $\hilbert$, When a $C^*$-algebra is represented on a Hilbert space $\hilbert$,
every unit vector $\psi \in \hilbert$ determines a (not necessarily pure) state in the form of an \defn{expectation value}, every unit vector $\psi \in \hilbert$ determines a (not necessarily pure) state in the form of an \defn{expectation value},
\begin{equation} \begin{equation}
\Psi(a) = \langle\psi, a\psi\rangle. \Psi(a) = \langle\psi, a\psi\rangle.
\end{equation} \end{equation}
In physics, it is common to refer to such states by their vector $\psi$ rather than the linear functional $\Psi$. In physics, it is common to refer to such states by their vector $\psi$ rather than the linear functional $\Psi$.
The converse is not always true; not every state need be given by The converse is not always true; not every state need be given by
an expectation value. an expectation value.
For example, delta functions (which are distributions not functions) For example, delta functions (which are distributions not functions)
give pure states on $C_0(X)$, give pure states on $C_0(X)$,
but they do not correspond to any vector in a Hilbert space but they do not correspond to any vector in a Hilbert space
(such a vector would not be square-integrable). (such a vector would not be square-integrable).
\begin{thebibliography}{10} \begin{thebibliography}{10}
\bibitem{Murphy} \bibitem{Murphy}
G.~Murphy, {\em $C^*$-Algebras and Operator Theory}. G.~Murphy, {\em $C^*$-Algebras and Operator Theory}.
\newblock Academic Press, 1990. \newblock Academic Press, 1990.
\end{thebibliography} \end{thebibliography}