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Revision difference : proof of Prohorov inequality
Version 3 Version 2
Starting from the basic inequality $\exp \left( -x\right) \geq 1-x$, it's Starting from the basic inequality $\exp \left( -x\right) \geq 1-x$, it's
easy to derive by elementary algebraic manipulations the two inequalities easy to derive by elementary algebraic manipulations the two inequalities
\begin{eqnarray*} \begin{eqnarray*}
\exp \left( x\right) -x-1 &\leq &2\left( \cosh \left( x\right) -1\right) \\ \exp \left( x\right) -x-1 &\leq &2\left( \cosh \left( x\right) -1\right) \\
2\left( \cosh \left( x\right) -1\right) &\leq &x\sinh \left( x\right) 2\left( \cosh \left( x\right) -1\right) &\leq &x\sinh \left( x\right)
\end{eqnarray*} \end{eqnarray*}
By the \PMlinkname{Chernoff-Cram\`{e}r bound}{ChernoffCramerBound}, we have: By the \PMlinkname{Chernoff-Cram\`{e}r bound}{ChernoffCramerBound}, we have:
\[ \[
\Pr\left\{ \sum_{i=1}^{n}\left( X_{i}-E[X_{i}]\right) >\varepsilon \right\} \Pr\left\{ \sum_{i=1}^{n}\left( X_{i}-E[X_{i}]\right) >\varepsilon \right\}
\leq \exp \left[ -\sup_{t>0}\left( t\varepsilon -\psi (t)\right) \right] \leq \exp \left[ -\sup_{t>0}\left( t\varepsilon -\psi (t)\right) \right]
\] \]
where where
\[ \[
\psi (t)=\sum_{i=1}^{n}\left( \ln E\left[ e^{tX_{i}}\right] -tE\left[ X_{i}% \psi (t)=\sum_{i=1}^{n}\left( \ln E\left[ e^{tX_{i}}\right] -tE\left[ X_{i}%
\right] \right) \right] \right)
\] \]
Since $\ln x\leq x-1$ $\forall x > 0$, Since $\ln x\leq x-1$ $\forall x > 0$,
\begin{eqnarray*} \begin{eqnarray*}
\psi (t) &=&\sum_{i=1}^{n}\left( \ln E\left[ e^{tX_{i}}\right] -tE\left[ \psi (t) &=&\sum_{i=1}^{n}\left( \ln E\left[ e^{tX_{i}}\right] -tE\left[
X_{i}\right] \right) \leq \\ X_{i}\right] \right) \leq \\
&\leq &\sum_{i=1}^{n}E\left[ e^{tX_{i}}\right] -tE\left[ X_{i}\right] -1= \\ &\leq &\sum_{i=1}^{n}E\left[ e^{tX_{i}}\right] -tE\left[ X_{i}\right] -1= \\
&=&\sum_{i=1}^{n}E\left[ e^{tX_{i}}-tX_{i}-1\right] \leq \\ &=&\sum_{i=1}^{n}E\left[ e^{tX_{i}}-tX_{i}-1\right] \leq \\
&\leq &\sum_{i=1}^{n}2E\left[ \cosh \left( tX_{i}\right) -1\right] \leq \\ &\leq &\sum_{i=1}^{n}2E\left[ \cosh \left( tX_{i}\right) -1\right] \leq \\
&\leq &\sum_{i=1}^{n}E\left[ tX_{i}\sinh \left( tX_{i}\right) \right] \leq \\ &\leq &\sum_{i=1}^{n}E\left[ tX_{i}\sinh \left( tX_{i}\right) \right] \leq \\
&\leq &\sum_{i=1}^{n}E\left[ \left\vert tX_{i}\sinh \left( tX_{i}\right) &\leq &\sum_{i=1}^{n}E\left[ \left\vert tX_{i}\sinh \left( tX_{i}\right)
\right\vert \right] = \\ \right\vert \right] = \\
&=&\sum_{i=1}^{n}tE\left[ \left\vert X_{i}\right\vert \sinh \left( &=&\sum_{i=1}^{n}tE\left[ \left\vert X_{i}\right\vert \sinh \left(
t\left\vert X_{i}\right\vert \right) \right] = \\ t\left\vert X_{i}\right\vert \right) \right] = \\
&=&\sum_{i=1}^{n}tE\left[ \sum_{k=0}^{\infty }\frac{t^{2k+1}\left\vert &=&\sum_{i=1}^{n}tE\left[ \sum_{k=0}^{\infty }\frac{t^{2k+1}\left\vert
X_{i}\right\vert ^{2k+2}}{\left( 2k+1\right) !}\right] = \\ X_{i}\right\vert ^{2k+2}}{\left( 2k+1\right) !}\right] = \\
&=&\sum_{i=1}^{n}t\sum_{k=0}^{\infty }\frac{t^{2k+1}E\left[ &=&\sum_{i=1}^{n}t\sum_{k=0}^{\infty }\frac{t^{2k+1}E\left[
X_{i}^{2}\left\vert X_{i}\right\vert ^{2k}\right] }{\left( 2k+1\right) !}\leq X_{i}^{2}\left\vert X_{i}\right\vert ^{2k}\right] }{\left( 2k+1\right) !}\leq
\\ \\
&=&\sum_{i=1}^{n}t\sum_{k=0}^{\infty }\frac{t^{2k+1}E\left[ X_{i}^{2}\right] &=&\sum_{i=1}^{n}t\sum_{k=0}^{\infty }\frac{t^{2k+1}E\left[ X_{i}^{2}\right]
M^{2k}}{\left( 2k+1\right) !}= \\ M^{2k}}{\left( 2k+1\right) !}= \\
&=&\frac{t}{M}\sum_{k=0}^{\infty }\frac{t^{2k+1}M^{2k+1}\sum_{i=1}^{n}E\left[ &=&\frac{t}{M}\sum_{k=0}^{\infty }\frac{t^{2k+1}M^{2k+1}\sum_{i=1}^{n}E\left[
X_{i}^{2}\right] }{\left( 2k+1\right) !}= \\ X_{i}^{2}\right] }{\left( 2k+1\right) !}= \\
&=&\frac{tv^{2}}{M}\sum_{k=0}^{\infty }\frac{\left( tM\right) ^{2k+1}}{% &=&\frac{tv^{2}}{M}\sum_{k=0}^{\infty }\frac{\left( tM\right) ^{2k+1}}{%
\left( 2k+1\right) !}= \\ \left( 2k+1\right) !}= \\
&=&\frac{tv^{2}}{M}\sinh \left( tM\right) . &=&\frac{tv^{2}}{M}\sinh \left( tM\right) .
\end{eqnarray*} \end{eqnarray*}
One can now write One can now write
\[ \[
\sup_{t>0}\left( t\varepsilon -\psi (t)\right) \geq \sup_{t>0}\left( \sup_{t>0}\left( t\varepsilon -\psi (t)\right) \geq \sup_{t>0}\left(
t\varepsilon -\frac{tv^{2}}{M}\sinh \left( tM\right) \right) =\sup_{t>0}% t\varepsilon -\frac{tv^{2}}{M}\sinh \left( tM\right) \right) =\sup_{t>0}%
\left[ \frac{v^{2}}{M^{2}}\left( \frac{M^{2}\varepsilon }{v^{2}}t-tM\sinh \left[ \frac{v^{2}}{M^{2}}\left( \frac{M^{2}\varepsilon }{v^{2}}t-tM\sinh
\left( tM\right) \right) \right] \left( tM\right) \right) \right]
\] \]
Optimizing this expression with respect to $t$ would lead to solving the Optimizing this expression with respect to $t$ would lead to solving the
trascendental equation: trascendental equation:
\[ \[
\frac{M\varepsilon }{v^{2}}=Mt_{opt}\cosh \left( Mt_{opt}\right) +\sinh \frac{M\varepsilon }{v^{2}}=Mt_{opt}\cosh \left( Mt_{opt}\right) +\sinh
\left( Mt_{opt}\right) \left( Mt_{opt}\right)
\] \]
which is analytically infeasible. So, one can choose the sup-optimal yet which is analytically infeasible. So, one can choose the sup-optimal yet
manageable solution manageable solution
\[ \[
\widetilde{t}=\frac{1}{M}\arcsinh\left( \frac{M\varepsilon }{2v^{2}}\right) \widetilde{t}=\frac{1}{M}\arcsin h\left( \frac{M\varepsilon }{2v^{2}}\right)
\] \]
which, once plugged into the bound, yields which, once plugged into the bound, yields
\[ \[
\Pr\left\{ \sum_{i=1}^{n}\left( X_{i}-E[X_{i}]\right) >\varepsilon \right\} \Pr\left\{ \sum_{i=1}^{n}\left( X_{i}-E[X_{i}]\right) >\varepsilon \right\}
\leq \exp \left[ -\frac{v^{2}}{M^{2}}\left( \frac{M\varepsilon }{2v^{2}}% \leq \exp \left[ -\frac{v^{2}}{M^{2}}\left( \frac{M\varepsilon }{2v^{2}}%
\arcsinh\left( \frac{M\varepsilon }{2v^{2}}\right) \right) \right] \arcsin h\left( \frac{M\varepsilon }{2v^{2}}\right) \right) \right]
\] \]