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Revision difference : pseudometric topology
Version current Version 3
Let $(X,d)$ be a pseudometric space. As in a metric space, we define Let $(X,d)$ be a pseudometric space. As in a metric space, we define
$$ $$
B_\varepsilon(x)=\{ y\in X\mid d(x,y)<\varepsilon \}. B_\varepsilon(x)=\{ y\in X\mid d(x,y)<\varepsilon \}.
$$ $$
for $x\in X$, $\varepsilon>0$. for $x\in X$, $\varepsilon>0$.
In the below, we show that the collection of sets In the below, we show that the collection of sets
$$ $$
\mathscr{B}= \{ B_\varepsilon(x)\mid \varepsilon>0, x\in X\} \mathscr{B}= \{ B_\varepsilon(x)\mid \varepsilon>0, x\in X\}
$$ $$
form a base for a topology for $X$. We call this topology form a base for a topology for $X$. We call this topology
the \PMlinkescapetext{\emph{pseudometric topology}} on $X$ the \PMlinkescapetext{\emph{pseudometric topology}} on $X$
induced by $d$. Also, induced by $d$. Also,
a topological space $X$ is a \emph{pseudometrizable topological space} a topological space $X$ is a \emph{pseudometrizable topological space}
if there exists a pseudometric $d$ on $X$ whose if there exists a pseudometric $d$ on $X$ whose
pseudometric topology coincides with the given topology pseudometric topology coincides with the given topology
for $X$ \cite{kelley, willard}. for $X$ \cite{kelley, willard}.
\begin{prop} \begin{prop}
$\mathscr{B}$ is a base for a topology. $\mathscr{B}$ is a base for a topology.
\end{prop} \end{prop}
\begin{proof} We shall use the \PMlinkid{this result}{5845} \begin{proof} We shall use the \PMlinkid{this result}{5845}
to prove that $\mathscr{B}$ is a base. to prove that $\mathscr{B}$ is a base.
First, as $d(x,x)=0$ for all $x\in X$, it follows First, as $d(x,x)=0$ for all $x\in X$, it follows
that $\mathscr{B}$ is a cover. that $\mathscr{B}$ is a cover.
Second, suppose $B_1,B_2\in \mathscr{B}$ and $z\in B_1\cap B_2$. Second, suppose $B_1,B_2\in \mathscr{B}$ and $z\in B_1\cap B_2$.
We claim that there exists a $B_3\in \mathscr{B}$ such that We claim that there exists a $B_3\in \mathscr{B}$ such that
\begin{eqnarray} \begin{eqnarray}
\label{ii} \label{ii}
z&\in& B_3\subseteq B_1\cap B_2. z&\in& B_3\subseteq B_1\cap B_2.
\end{eqnarray} \end{eqnarray}
By definition, $B_1 = B_{\varepsilon_1}(x_1)$ By definition, $B_1 = B_{\varepsilon_1}(x_1)$
and $B_2 = B_{\varepsilon_2}(x_2)$ for some $x_1,x_2\in X$ and $B_2 = B_{\varepsilon_2}(x_2)$ for some $x_1,x_2\in X$
and $\varepsilon_1,\varepsilon_2>0$. Then and $\varepsilon_1,\varepsilon_2>0$. Then
$$ $$
d(x_1, z)<\varepsilon_1, \quad d(x_2, z)<\varepsilon_2. d(x_1, z)<\varepsilon_1, \quad d(x_2, z)<\varepsilon_2.
$$ $$
Now we can define $\delta = \min\{ \varepsilon_1-d(x_1, z), \varepsilon_2-d(x_2, z)\}>0$, and put Now we can define $\delta = \min\{ \varepsilon_1-d(x_1, z), \varepsilon_2-d(x_2, z)\}>0$, and put
$$ $$
B_3 = B_\delta(z). B_3 = B_\delta(z).
$$ $$
If $y\in B_3$, then for $k=1,2$, we have by the triangle inequality If $y\in B_3$, then for $k=1,2$, we have by the triangle inequality
\begin{eqnarray*} \begin{eqnarray*}
d(x_k,y) &\le & d(x_k, z) + d(z,y) \\ d(x_k,y) &\le & d(x_k, z) + d(z,y) \\
&< & d(x_k, z) + \delta \\ &< & d(x_k, z) + \delta \\
&\le & \varepsilon_k, &\le & \varepsilon_k,
\end{eqnarray*} \end{eqnarray*}
so $B_3\subseteq B_k$ and condition \ref{ii} holds. so $B_3\subseteq B_k$ and condition \ref{ii} holds.
\end{proof} \end{proof}
\subsubsection*{Remark} \subsubsection*{Remark}
In the proof, we have not used the fact that $d$ is In the proof, we have not used the fact that $d$ is
symmetric. Therefore, we have, in fact, also shown that any symmetric. Therefore, we have, in fact, also shown that any
quasimetric induces a topology. quasimetric induces a topology.
\begin{thebibliography}{9} \begin{thebibliography}{9}
\bibitem{kelley} J.L. Kelley, \emph{General Topology}, \bibitem{kelley} J.L. Kelley, \emph{General Topology},
D. van Nostrand Company, Inc., 1955. D. van Nostrand Company, Inc., 1955.
\bibitem{willard} S. Willard, \emph{General Topology}, \bibitem{willard} S. Willard, \emph{General Topology},
Addison-Wesley, Publishing Company, 1970. Addison-Wesley, Publishing Company, 1968.
\end{thebibliography} \end{thebibliography}