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Revision difference : Banach algebra
Version 6 Version 5
\begin{definition} \begin{definition}
A \textbf{Banach algebra} $\mathcal{A}$ is a Banach space with an multiplication law compatible with the norm which turns $A$ into an algebra. Compatibility with the norm means that, for all $a,b \in \mathcal{B}$, it is the case that the following product inequality holds: A \textbf{Banach algebra} is a Banach space with a multiplication law
\[ \norm{ab} \leq \norm{a}\,\norm{b} \] compatible with the norm, i.e.\ $\norm{ab} \leq \norm{a}\,\norm{b}$ (product inequality).
\end{definition} \end{definition}
\begin{definition} \begin{definition}
A \textbf{Banach *-algebra} is a Banach algebra with a map ${}^* \colon A \to A$ which satisfies the following properties: A \textbf{Banach *-algebra} is a Banach algebra with an involution ${}^*$
satisfying the following properties:
\begin{eqnarray} \begin{eqnarray}
a^{**} & = & a, \\ a^{**} & = & a, \\
(ab)^* & = & b^* a^*, \\ (ab)^* & = & b^* a^*, \\
(\lambda a+\mu b)^* & = & \bar{\lambda} a^*+\bar{\mu} b^* \quad\forall\lambda,\mu\in\Cset, \\ (\lambda a+\mu b)^* & = & \bar{\lambda} a^*+\bar{\mu} b^* \quad\forall\lambda,\mu\in\Cset, \\
\norm{a^*} & = & \norm{a}. \norm{a^*} & = & \norm{a}.
\end{eqnarray} \end{eqnarray}
\end{definition} \end{definition}
\begin{example} \begin{example}
The algebra of bounded operators on a Banach space is a Banach algebra The algebra of bounded operators on a Banach space is a Banach algebra
for the operator norm. for the operator norm.
\end{example} \end{example}