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A \emph{prismatoid} is a polyhedron, possibly not convex, whose vertices all lie in one or the other A \emph{prismatoid} is a polyhedron, possibly not convex, whose vertices all lie in one or the other
of two parallel planes. of two parallel planes.
The perpendicular distance between the two planes is called the \emph{altitude} The perpendicular distance between the two planes is called the \emph{altitude}
of the prismatoid. of the prismatoid.
The faces that lie in the parallel planes are called the \emph{bases} The faces that lie in the parallel planes are called the \emph{bases}
of the prismatoid. of the prismatoid.
The \emph{midsection} is the polygon formed by cutting the prismatoid by The \emph{midsection} is the polygon formed by cutting the prismatoid by
a plane parallel to the bases halfway between them. a plane parallel to the bases halfway between them.
The volume of a prismatoid is given by the \emph{prismoidal formula}: The volume of a prismatoid is given by the prismoidal formula:
$$ $$
V = \frac{1}{6} h(B_1 + B_2 + 4M) V = \frac{1}{6} h(B_1 + B_2 + 4M)
$$ $$
where $h$ is the altitude, $B_1$ and $B_1$ are the areas of the bases and $M$ where $h$ is the altitude, $B_1$ and $B_1$ are the areas of the bases and $M$
is the area of the midsection. is the area of the midsection.
An alternate formula is : An alternate formula is :
$$ $$
V = \frac{1}{4}h ( B_1 + 3S) V = \frac{1}{4}h ( B_1 + 3S)
$$ $$
where $S$ is the area of the polygon that is formed by cutting the prismatoid where $S$ is the area of the polygon that is formed by cutting the prismatoid
by a plane parallel to the bases but 2/3 of the distance from $B_1$ to $B_2$. by a plane parallel to the bases but 2/3 of the distance from $B_1$ to $B_2$.
A proof of the prismoidal formula for the case where A proof of the prismoidal formula is in \cite{Br}. It is also proved in \cite{Ha}.
the prismatoid is convex is in \cite{Br}. It is also proved in \cite{Ha} for any prismatoid.
The alternate formula is proved in \cite{Ha}. The alternate formula is proved in \cite{Ha}.
Some authors impose the condition that the lateral faces must be triangles Some authors impose the condition that the lateral faces must be triangles
or trapezoids. However, this condition is unnecessary since it is easily shown or trapezoids. However, this condition is unnecessary since it is easily show
to hold. to hold.
\begin{thebibliography}{99} \begin{thebibliography}{99}
\bibitem{Br} \bibitem{Br}
A. Day Bradley, Prismatoid, Prismoid, Generalized Prismoid, \emph{The American Math. Monthly,} A. Day Bradley, Prismatoid, Prismoid, Generalized Prismoid, \emph{The American Math. Monthly,}
\textbf{86}, (1979), 486-490. \textbf{86}, (1979), 486-490.
\bibitem{Ha} \bibitem{Ha}
G.B. Halsted, \emph{Rational Geometry: A textbook for the Science of Space. Based on G.B. Halsted, \emph{Rational Geometry: A textbook for the Science of Space. Based on
Hilbert's Foundations}, second edition, John Wiley and Sons, New York, 1907 Hilbert's Foundations}, second edition, John Wiley and Sons, New York, 1907
\end{thebibliography} \end{thebibliography}