PlanetMath (more info)
 Math for the people, by the people. Sponsor PlanetMath
Encyclopedia | Requests | Forums | Docs | Wiki | Random | RSS  
Login
create new user
name:
pass:
forget your password?
Main Menu
Revision difference : ordered group
Version 7 Version 6
\textbf{Definition 1.} \,We say that the subsemigroup $S$ of the group $G$ (with the operation denoted multiplicatively) defines an \PMlinkescapetext{{\em order for the group}} $G$, if \textbf{Definition 1.} \,We say that the subsemigroup $S$ of the group $G$ (with the operation denoted multiplicatively) defines an \PMlinkescapetext{{\em order for the group}} $G$, if
\begin{itemize} \begin{itemize}
\item $a^{-1}Sa \subseteq S \quad \forall a\in G,$ \item $a^{-1}Sa \subseteq S \quad \forall a\in G,$
\item $G = S\cup \{1\} \cup S^{-1}$ \,\,where \,$S^{-1} = \{s^{-1}: \,s\in S\}$\, and the members of the union are pairwise disjoint. \item $G = S\cup \{1\} \cup S^{-1}$ \,\,where \,$S^{-1} = \{s^{-1}: \,s\in S\}$\, and the members of the union are pairwise disjoint.
\end{itemize} \end{itemize}
The order ``$<$'' of the group $G$ is explicitely given by setting in $G$: The order ``$<$'' of the group $G$ is explicitely given by setting in $G$:
$$a < b \,\, \Leftrightarrow \,\,ab^{-1}\in S$$ $$a < b \,\, \Leftrightarrow \,\,ab^{-1}\in S$$
Then we speak of the {\em ordered group} $(G,\,<)$ or simply $G$. Then we speak of the {\em ordered group} $(G,\,<)$ or simply $G$.
\begin{thmplain} \textbf{Theorem.} \,The order ``$<$'' defined by the subsemigroup $S$ of the group $G$ has the following properties.
\,\,The order ``$<$'' defined by the subsemigroup $S$ of the group $G$ has the following properties.
\begin{enumerate} \begin{enumerate}
\item For all \,$a,\,b\in G$, exactly one of the conditions \,\,$a < b,\,\,a = b,\,\,b < a$\,\, holds. \item For all \,$a,\,b\in G$, exactly one of the conditions \,\,$a < b,\,\,a = b,\,\,b < a$\,\, holds.
\item $a < b \,\land\, b < c \,\,\Rightarrow\,\,a < c$ \item $a < b \,\land\, b < c \,\,\Rightarrow\,\,a < c$
\item $a < b \,\,\Rightarrow\,\, ac < bc \,\land\, ca < cb$ \item $a < b \,\,\Rightarrow\,\, ac < bc \,\land\, ca < cb$
\item $a < b \,\land\, c < d \,\,\Rightarrow\,\, ac < bd$ \item $a < b \,\land\, c < d \,\,\Rightarrow\,\, ac < bd$
\item $a < b \,\,\Leftrightarrow\,\, b^{-1} < a^{-1}$ \item $a < b \,\,\Leftrightarrow\,\, b^{-1} < a^{-1}$
\item $a < 1 \,\,\Leftrightarrow\,\, a\in S$ \item $a < 1 \,\,\Leftrightarrow\,\, a\in S$
\end{enumerate} \end{enumerate}
\end{thmplain}
\textbf{Definition 2.} \,The set $G$ is an {\em ordered group equipped with zero} 0, if the set $G^*$ of its elements distinct from its element 0 form an ordered group \,$(G^*,\,<)$\, and if \textbf{Definition 2.} \,The set $G$ is an {\em ordered group equipped with zero} 0, if the set $G^*$ of its elements distinct from its element 0 form an ordered group \,$(G^*,\,<)$\, and if
\begin{itemize} \begin{itemize}
\item $0a = a0 = 0 \quad\forall a\in G,$ \item $0a = a0 = 0 \quad\forall a\in G,$
\item $0 < a \quad\forall a\in G^*.$ \item $0 < a \quad\forall a\in G^*.$
\end{itemize} \end{itemize}
\begin{thebibliography}{9}
\bibitem{artin} Emil Artin: {\em Theory of Algebraic Numbers}. \,Lecture notes. \,Mathematisches Institut, G\"ottingen (1959). \subsection*{References}
\bibitem{Jaffard} Paul Jaffard: {\em Les syst\`emes d'id\'eaux}. \,Dunod, Paris (1960). Emil Artin: {\em Theory of Algebraic Numbers}. \,Lecture notes. \,Mathematisches Institut, G\"ottingen (1959).
\end{thebibliography}
Paul Jaffard: {\em Les syst\`emes d'id\'eaux}. \,Dunod, Paris (1960).