PlanetMath (more info)
 Math for the people, by the people. Sponsor PlanetMath
Encyclopedia | Requests | Forums | Docs | Wiki | Random | RSS  
Login
create new user
name:
pass:
forget your password?
Main Menu
Revision difference : Dirac equation
Version 8 Version 7
The Dirac equation is an equation derived by Paul Dirac in 1927 that describes relativistic spin $1/2$ particles (fermions). It is given by: The Dirac equation is an equation derived by Paul Dirac in 1927 that describes relativistic spin $1/2$ particles (fermions). It is given by:
\[ \[
(\gamma^\mu \partial_\mu - im)\psi = 0 (\gamma^\mu \partial_\mu - im)\psi = 0
\] \]
The Einstein summation convention is used. The Einstein summation convention is used.
\subsection{Derivation} \subsection{Derivation}
Mathematically, it is interesting as one of the first uses of the spinor calculus in mathematical physics. Dirac began with the relativistic equation of total energy: Mathematically, it is interesting as one of the first uses of the spinor calculus in mathematical physics. Dirac began with the relativistic equation of total energy:
\[ \[
E = \sqrt{p^2c^2 + m^2c^4} E = \sqrt{p^2c^2 + m^2c^4}
\] \]
As Schr\"odinger had done before him, Dirac then replaced $p$ with its quantum mechanical operator, $\hat{p} \Rightarrow i\hbar \nabla$. Since he was looking for a Lorentz-invariant equation, he replaced $\nabla$ with the D'Alembertian or wave operator As Schr\"odinger had done before him, Dirac then replaced $p$ with its quantum mechanical operator, $\hat{p} \Rightarrow i\hbar \nabla$. Since he was looking for a Lorentz-invariant equation, he replaced $\nabla$ with the D'Alembertian or wave operator
\[ \[
\Box = \nabla^2 - \frac{1}{c^2} \frac{\partial^2}{\partial t^2} \Box = \nabla^2 - \frac{1}{c^2} \frac{\partial^2}{\partial t^2}
\] \]
Note that some authors use $\Box^2$ for the D'alembertian. Dirac was now faced with the problem of how to take the square root of an expression containing a differential operator. He proceeded to factorise the d'Alembertian as follows: Note that some authors use $\Box^2$ for the D'alembertian. Dirac was now faced with the problem of how to take the square root of an expression containing a differential operator. He proceeded to factorise the d'Alembertian as follows:
\[ \[
\nabla^2 - \frac{1}{c^2} \frac{\partial^2}{\partial t^2} = (A \frac{\partial}{\partial x} + B \frac{\partial}{\partial y} + c \frac{\partial}{\partial z} + D\frac{i}{c} \frac{\partial}{\partial t})^2 \nabla^2 - \frac{1}{c^2} \frac{\partial^2}{\partial t^2} = (A \frac{\partial}{\partial x} + B \frac{\partial}{\partial y} + c \frac{\partial}{\partial z} + D\frac{i}{c} \frac{\partial}{\partial t})^2
\] \]
Multiplying this out, we find that: Multiplying this out, we find that:
\[ \[
A^2 = B^2 = C^2 = D^2 = 1 A^2 = B^2 = C^2 = D^2 = 1
\] \]
And And
\[ \[
AB + BA = BC + CB = CD + DC = 0 AB + BA = BC + CB = CD + DC = 0
\] \]
Clearly these relations cannot be satisfied by scalars, so Dirac sought a set of four matrices which satisfy these relations. These are now known as the Dirac matrices, and are given as follows: Clearly these relations cannot be satisfied by scalars, so Dirac sought a set of four matrices which satisfy these relations. These are now known as the Dirac matrices, and are given as follows:
\[ \[
A = A =
\begin{pmatrix} \begin{pmatrix}
1 & 0 & 0 & 0 \\ 1 & 0 & 0 & 0 \\
0 & 1 & 0 & 0 \\ 0 & 1 & 0 & 0 \\
0 & 0 & -1 & 0 \\ 0 & 0 & -1 & 0 \\
0 & 0 & 0 & -1 \end{pmatrix}, 0 & 0 & 0 & -1 \end{pmatrix},
B = \begin{pmatrix} B = \begin{pmatrix}
0 & 0 & 0 & 1 \\ 0 & 0 & 0 & 1 \\
0 & 0 & 1 & 0 \\ 0 & 0 & 1 & 0 \\
0 & -1 & 0 & 0 \\ 0 & -1 & 0 & 0 \\
-1 & 0 & 0 & 0 \end{pmatrix} -1 & 0 & 0 & 0 \end{pmatrix}
\] \]
\[ \[
C = \begin{pmatrix} C = \begin{pmatrix}
0 & 0 & 0 & -i \\ 0 & 0 & 0 & -i \\
0 & 0 & i & 0 \\ 0 & 0 & i & 0 \\
0 & i & 0 & 0 \\ 0 & i & 0 & 0 \\
-i & 0 & 0 & 0 \end{pmatrix}, -i & 0 & 0 & 0 \end{pmatrix},
D = \begin{pmatrix} D = \begin{pmatrix}
0 & 0 & 1 & 0 \\ 0 & 0 & 1 & 0 \\
0 & 0 & 0 & -1 \\ 0 & 0 & 0 & -1 \\
-1 & 0 & 0 & 0 \\ -1 & 0 & 0 & 0 \\
0 & 1 & 0 & 0 \end{pmatrix} 0 & 1 & 0 & 0 \end{pmatrix}
\] \]
These matrices are usually given the symbols $\gamma^0$, $\gamma^1$, etc. They are also known as the generators of the special unitary group of order 4, i.e. the group of $n \times n$ matrices with unit determinant. These matrices are usually given the symbols $\gamma^0$, $\gamma^1$, etc. They are also known as the generators of the special unitary group of order 4, i.e. the group of $n \times n$ matrices with unit determinant.
Using these matrices, and switching to natural units ($\hbar = c = 1$) we can now obtain the Dirac equation: Using these matrices, and switching to natural units ($\hbar = c = 1$) we can now obtain the Dirac equation:
\[ \[
(\gamma^\mu \partial_\mu - im)\psi = 0 (\gamma^\mu \partial_\mu - im)\psi = 0
\] \]
\subsection{Feynman slash notation} \subsection{Feynman slash notation}
Richard Feynman developed the following convenient notation for terms involving Dirac matrices: Richard Feynman developed the following convenient notation for terms involving Dirac matrices:
\[ \[
\gamma^\mu q_\mu = \cancel{q} \gamma^\mu q_\mu = \cancel{q}
\] \]
Using this notation, the Dirac equation is simply Using this notation, the Dirac equation is simply
\[ \[
(\cancel{\partial} - im)\psi = 0 (\cancel{\partial} - im)\psi = 0
\] \]