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There are many definitions of an orientation of a manifold. The most general, in the sense that it doesn't require any extra \PMlinkescapetext{structure} on the manifold, is based on There are many definitions of an orientation of a manifold. The most general, in the sense that it doesn't require any extra structure on the manifold, is based on
(co-)homology theory. For this article manifold means a connected, {\em topological} manifold possibly (co-)homology theory. For this article manifold means a connected, {\em topological} manifold possibly
with boundary. with boundary.
\begin{thm} Let $M$ be a closed, $n$--dimensional manifold. Then $H_n(M\,;\mathbb{Z})$ the \begin{thm} Let $M$ be a closed, $n$--dimensional manifold. Then $H_n(M\,;\mathbb{Z})$ the
top dimensional homology group of $M$, is either trivial top dimensional homology group of $M$, is either trivial
($\{0\}$) or isomorphic to $ \mathbb{Z}$. ($\{0\}$) or isomorphic to $ \mathbb{Z}$.
\end{thm} \end{thm}
\begin{defn} A closed $n$--manifold is called orientable if its top \begin{defn} A closed $n$--manifold is called orientable if its top
homology group is isomorphic to the integers.\newline homology group is isomorphic to the integers.\newline
An orientation of $M$ is a choice of a particular isomorphism An orientation of $M$ is a choice of a particular isomorphism
$$\mathfrak{o}\co \mathbb{Z} \to H_n(M\,;\mathbb{Z}).$$ $$\mathfrak{o}\co \mathbb{Z} \to H_n(M\,;\mathbb{Z}).$$
An oriented manifold is a (necessarily orientable) manifold $M$ endowed with An oriented manifold is a (necessarily orientable) manifold $M$ endowed with
an orientation. \newline an orientation. \newline
If $(M,\mathfrak{o})$ is an oriented manifold then $\mathfrak{o}(1)$ is called If $(M,\mathfrak{o})$ is an oriented manifold then $\mathfrak{o}(1)$ is called
the fundamental class of $M$ , or the orientation class of $M$, and is denoted the fundamental class of $M$ , or the orientation class of $M$, and is denoted
by $[M]$. by $[M]$.
\end{defn} \end{defn}
\begin{rem} Notice that since $\mathbb{Z}$ has exactly two automorphisms an orientable manifold admits two possible orientations. \begin{rem} Notice that since $\mathbb{Z}$ has exactly two automorphisms an orientable manifold admits two possible orientations.
\end{rem} \end{rem}
\begin{rem} The above definition could be given using cohomology instead of homology. \begin{rem} The above definition could be given using cohomology instead of homology.
\end{rem} \end{rem}
The top dimensional homology of a non-closed manifold is always trivial, so it is trickier to define orientation for those beasts. One approach (which we will The top dimensional homology of a non-closed manifold is always trivial, so it is trickier to define orientation for those beasts. One approach (which we will
not follow) is to use special kind of homology (for example relative to the boundary for compact manifolds with boundary). The approach we follow defines not follow) is to use special kind of homology (for example relative to the boundary for compact manifolds with boundary). The approach we follow defines
(global) orientation as compatible fitting together of local orientations. We start with (global) orientation as compatible fitting together of local orientations. We start with
manifolds without boundary. manifolds without boundary.
\begin{thm}Let $M$ be an $n$-manifold without boundary and $x\in M$. Then the relative homology \begin{thm}Let $M$ be an $n$-manifold without boundary and $x\in M$. Then the relative homology
group group
$$H_n(M,M\setminus x\,;\mathbb{Z}) \cong \mathbb{Z}$$ $$H_n(M,M\setminus x\,;\mathbb{Z}) \cong \mathbb{Z}$$
\end{thm} \end{thm}
\begin{defn} Let $M$ be an $n$-manifold and $x\in M$. An {\em orientation \begin{defn} Let $M$ be an $n$-manifold and $x\in M$. An {\em orientation
of} $M$ {\em at} $x$ is a choice of an isomorphism of} $M$ {\em at} $x$ is a choice of an isomorphism
$$\mathfrak{o}_x \co \mathbb{Z} \to H_n(M,M\setminus x\,;\mathbb{Z}).$$ $$\mathfrak{o}_x \co \mathbb{Z} \to H_n(M,M\setminus x\,;\mathbb{Z}).$$
\end{defn} \end{defn}
\PMlinkescapetext{One way} to make precise the notion of nicely fitting together of orientations at points, is to One way to make precise the notion of nicely fitting together of orientations at points, is to
require that for nearby points the orientations are defined in a \PMlinkescapetext{uniform} way. require that for nearby points the orientations are defined in a uniform way.
\begin{thm} \begin{thm}
Let $U$ be an open subset of $M$ that is homeomorphic to $\BR^n$ (e.g. the domain of a chart). Let $U$ be an open subset of $M$ that is homeomorphic to $\BR^n$ (e.g. the domain of a chart).
Then, Then,
$$H_n(M,M\setminus U \,; \BZ)\cong \BZ.$$ $$H_n(M,M\setminus U \,; \BZ)\cong \BZ.$$
\end{thm} \end{thm}
\begin{defn} Let $U$ be an open subset of $M$ that is homeomorphic to $\BR^n$. A local orientation \begin{defn} Let $U$ be an open subset of $M$ that is homeomorphic to $\BR^n$. A local orientation
of $M$ on $U$ is a choice of an isomorphism of $M$ on $U$ is a choice of an isomorphism
$$\mathfrak{o}_U \co H_n(M,M\setminus U \,; \BZ) \to \BZ.$$ $$\mathfrak{o}_U \co H_n(M,M\setminus U \,; \BZ) \to \BZ.$$
\end{defn} \end{defn}
Now notice that with $U$ as above and $x\in U$ the inclusion Now notice that with $U$ as above and $x\in U$ the inclusion
$$\imath^U_x\co M\setminus U \hookrightarrow M\setminus x$$ $$\imath^U_x\co M\setminus U \hookrightarrow M\setminus x$$
\PMlinkescapetext{induces} a map (actually isomorphism) induces a map (actually isomorphism)
$$\imath^U_{x\,\,*}\co H_n(M,M\setminus U \,; \BZ) \to H_n(M,M\setminus x\,;\mathbb{Z})$$ $$\imath^U_{x\,\,*}\co H_n(M,M\setminus U \,; \BZ) \to H_n(M,M\setminus x\,;\mathbb{Z})$$
and therefore a local orientation at $U$ \PMlinkescapetext{induces} (by composing with the above isomorphism) and therefore a local orientation at $U$ induces (by composing with the above isomorphism)
an orientation at each point $x\in U$. It is \PMlinkescapetext{natural} to declare that all these orientations an orientation at each point $x\in U$. It is natural to declare that all these orientations
fit nicely together. fit nicely together.
\begin{defn} \begin{defn}
Let $M$ be a manifold without boundary. An orientation of $M$ is a choice of an orientation Let $M$ be a manifold without boundary. An orientation of $M$ is a choice of an orientation
$\mathfrak{o}_x$ for each point $x\in M$, with the property that $\mathfrak{o}_x$ for each point $x\in M$, with the property that
\begin{itemize} \begin{itemize}
\item[] each point $x$ has a coordinate neighborhood $U$ so that for each $y\in U$, the orientation \item[] each point $x$ has a coordinate neighborhood $U$ so that for each $y\in U$, the orientation
$\mathfrak{o}_y$ is induced by a local orientation on $U$. $\mathfrak{o}_y$ is induced by a local orientation on $U$.
\end{itemize} \end{itemize}
A manifold is called orientable if it admits an orientation. A manifold is called orientable if it admits an orientation.
\end{defn} \end{defn}
\begin{rem} \begin{rem}
Although we avoided using this terminology what we did was to indicate how a sheaf of orientations Although we avoided using this terminology what we did was to indicate how a sheaf of orientations
could be defined, and then we defined an orientation to be a global section of that sheaf. could be defined, and then we defined an orientation to be a global section of that sheaf.
\end{rem} \end{rem}
\begin{defn} \begin{defn}
Let $M$ be a manifold with non-empty boundary, $\partial M\neq \emptyset$. $M$ is called Let $M$ be a manifold with non-empty boundary, $\partial M\neq \emptyset$. $M$ is called
orientable if its double orientable if its double
$$\hat{M}:=M\bigcup_{\partial M}M$$ $$\hat{M}:=M\bigcup_{\partial M}M$$
is orientable, where $\bigcup_{\partial M}$ denotes gluing along the boundary.\n is orientable, where $\bigcup_{\partial M}$ denotes gluing along the boundary.\n
An orientation of $M$ is determined by an orientation of $\hat{M}$. An orientation of $M$ is determined by an orientation of $\hat{M}$.
\end{defn} \end{defn}