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Revision difference : increasing/decreasing/monotone function
Version 8 Version 7
\newcommand{\sR}[0]{\mathbb{R}} \newcommand{\sR}[0]{\mathbb{R}}
\PMlinkescapeword{increasing} \PMlinkescapeword{increasing}
\PMlinkescapeword{strictly increasing} \PMlinkescapeword{strictly increasing}
\PMlinkescapeword{decreasing} \PMlinkescapeword{decreasing}
\PMlinkescapeword{strictly decreasing} \PMlinkescapeword{strictly decreasing}
\PMlinkescapeword{monotone} \PMlinkescapeword{monotone}
\PMlinkescapeword{strictly monotone} \PMlinkescapeword{strictly monotone}
{\bf Definition} {\bf Definition}
Let $A$ be a subset of $\sR$, and let $f$ be a function from $f:A\to \sR$. Let $A$ be a subset of $\sR$, and let $f$ be a function from $f:A\to \sR$.
Then Then
\begin{enumerate} \begin{enumerate}
\item $f$ is \emph{increasing} or \emph{weakly increasing}, if \item $f$ is \emph{increasing}increasing}, if
$x\le y$ implies that $f(x)\le f(y)$ (for all $x$ and $y$ in $A$). $x\le y$ implies that $f(x)\le f(y)$ (for all $x$ and $y$ in $A$).
\item $f$ is \emph{strictly increasing} or \emph{strongly increasing}, if \item $f$ is \emph{strictly increasing}ly increasing}, if
$x< y$ implies that $f(x)< f(y)$. $x< y$ implies that $f(x)< f(y)$.
\item $f$ is \emph{decreasing} or \emph{weakly decreasing}, if \item $f$ is \emph{decreasing}decreasing}, if
$x\le y$ implies that $f(x)\ge f(y)$. $x\le y$ implies that $f(x)\ge f(y)$.
\item $f$ is \emph{strictly decreasing} or \emph{strongly decreasing} if \item $f$ is \emph{strictly decreasing}, if
$x< y$ implies that $f(x)> f(y)$. $x< y$ implies that $f(x)> f(y)$.
\item $f$ is \emph{monotone}, \item $f$ is \emph{monotone},
if $f$ is either increasing or decreasing. if $f$ is either increasing or decreasing.
\item $f$ is \emph{strictly monotone} or \emph{strongly monotone}, \item $f$ is \emph{strictly monotone}ly monotone},
if $f$ is either strictly increasing or strictly decreasing. if $f$ is either strictly increasing or strictly decreasing.
\end{enumerate} \end{enumerate}
{\bf Theorem} Let $X$ be a bounded or unbounded open interval of $\sR$. {\bf Theorem} Let $X$ be a bounded or unbounded open interval of $\sR$.
In other words, let $X$ be an interval of the form $X=(a,b)$, where $a,b\in\sR\cup\{-\infty,\infty\}$. In other words, let $X$ be an interval of the form $X=(a,b)$, where $a,b\in\sR\cup\{-\infty,\infty\}$.
Futher, let $f:X\to \sR$ be a monotone function. Futher, let $f:X\to \sR$ be a monotone function.
\begin{enumerate} \begin{enumerate}
\item The set of points where $f$ is discontinuous is at most \item The set of points where $f$ is discontinuous is at most
countable \cite{aliprantis, rudin}. countable \cite{aliprantis, rudin}.
\item [Lebesgue] $f$ is differentiable almost \item [Lebesgue] $f$ is differentiable almost
everywhere (\cite{jones}, pp. 514). everywhere (\cite{jones}, pp. 514).
\end{enumerate} \end{enumerate}
\begin{thebibliography}{9} \begin{thebibliography}{9}
\bibitem{aliprantis} \bibitem{aliprantis}
C.D. Aliprantis, O. Burkinshaw, \emph{Principles of Real Analysis}, C.D. Aliprantis, O. Burkinshaw, \emph{Principles of Real Analysis},
2nd ed., Academic Press, 1990. 2nd ed., Academic Press, 1990.
\bibitem{rudin} \bibitem{rudin}
W. Rudin, \emph{Principles of Mathematical Analysis}, McGraw-Hill Inc., 1976. W. Rudin, \emph{Principles of Mathematical Analysis}, McGraw-Hill Inc., 1976.
\bibitem{jones} \bibitem{jones}
F. Jones, \emph{Lebesgue Integration on Euclidean Spaces}, F. Jones, \emph{Lebesgue Integration on Euclidean Spaces},
Jones and Barlett Publishers, 1993. Jones and Barlett Publishers, 1993.
\end{thebibliography} \end{thebibliography}