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Revision difference : abelian group
Version 8 Version 7
\PMlinkescapeword{properties} Let $(G,*)$ be a group. If for any $a,b\inG$ we have
\PMlinkescapeword{subgroup}
\PMlinkescapeword{subgroups}
Let $(G,*)$ be a group. If for any $a,b\in G$ we have
$a*b=b*a$, we say that the group is \emph{abelian}. Sometimes the expression \emph{commutative group} is used, but this is less frequent. $a*b=b*a$, we say that the group is \emph{abelian}. Sometimes the expression \emph{commutative group} is used, but this is less frequent.
Abelian groups hold several interesting properties. Abelian groups hold several interesting properties.
\begin{thm} \begin{thm}
If $\varphi\colon G\to G$ defined by $ \varphi(x) =x^2$ is an homomorphism, then $G$ is abelian If $\varphi:G\to G$ defined by $ \varphi(x) =x^2$ is an homomorphism, then $G$ is abelian
\end{thm} \end{thm}
If such mapping were a homomorphism, we would have If such mapping were a homomorphism, we would have
\[(xy)^2=\varphi(xy) = \varphi(x)\varphi(y)=x^2y^2\] \[(xy)^2=\varphi(xy) = \varphi(x)\varphi(y)=x^2y^2\]
that is, $xyxy=xxyy$. Left-mutiplying by $x^{-1}$ and right-multiplying by $y^{-1}$ we are led to that is, $xyxy=xxyy$. Left-mutiplying by $x^{-1}$ and right-multiplying by $y^{-1}$ we are led to
$yx=xy$ and thus the group is abelian. $yx=xy$ and thus the group is abelian.
\begin{thm} \begin{thm}
Any \PMlinkname{subgroup}{Subgroup} of an abelian group is normal. Any subgroup of an abelian group is normal.
\end{thm} \end{thm}
Let $H$ be a subgroup of the abelian group $G$. Since $ah=ha$ for any $a\in G$ and any $h\in H$ we get $aH=Ha$. That is, $H$ is normal in $G$. Let $H$ be a subgroup of the abelian group $G$. Since $ah=ha$ for any $a\inG$ and any $h\in H$ we get $aH=Ha$. That is, $H$ is normal in $G$.
\begin{thm} \begin{thm}
Quotient groups of abelian groups are also abelian Quotient groups of abelian groups are also abelian
\end{thm} \end{thm}
Let $H$ a subgroup of $G$. Since $G$ is abelian, $H$ is normal and we can get the quotient group $G/H$ whose elements are the equivalence classes for Let $H$ a subgroup of $G$. Since $G$ is abelian, $H$ is normal and we can get the quotient group $G/H$ whose elements are the equivalence classes for
$a\sim b$ if $ab^{-1}\in H$. $a\sim b$ if $ab^{-1}\in H$.
The operation on the quotient group is given by $aH\cdot bH=(ab)H$. But $bh\cdot aH=(ba)H =(ab)H$, therefore the quotient group is also commutative. The operation on the quotient group is given by $aH\cdot bH=(ab)H$. But $bh\cdot aH=(ba)H =(ab)H$, therefore the quotient group is also commutative.