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Revision difference : first-order theory
Version 10 Version 9
In what follows, references to sentences and sets of sentences are In what follows, references to sentences and sets of sentences are
all relative to some fixed first-order language.\\ all relative to some fixed first-order language.\\
\textbf{Definition.} A \textbf{theory} $T$ is a \emph{deductively \textbf{Definition.} A \textbf{theory} $T$ is a \emph{deductively
closed} set of sentences; that is, a set $T$ such that for each closed} set of sentences; that is, a set $T$ such that for each
sentence $\varphi$, $T \models \varphi$ only if $\varphi \in sentence $\varphi$, $T \models \varphi$ only if $\varphi \in
T$.\\ T$.\\
\textbf{Definition.} A theory $T$ is \emph{consistent} if and only \textbf{Definition.} A theory $T$ is \emph{consistent} if and only
if for some sentence $\varphi$, $T \not \models \varphi$. if for some sentence $\varphi$, $T \not \models \varphi$.
Otherwise, $T$ is \emph{inconsistent}. A sentence Otherwise, $T$ is \emph{inconsistent}. A sentence
$\varphi$ is \emph{consistent with $T$} if and only if the $\varphi$ is \emph{consistent with $T$} if and only if the
theory $T \cup \lbrace \varphi \rbrace$ is consistent.\\ theory $T \cup \lbrace \varphi \rbrace$ is consistent.\\
\textbf{Definition.} A theory $T$ is \emph{complete} if and only \textbf{Definition.} A theory $T$ is \emph{complete} if and only
if for each sentence $\varphi$, either $\varphi \in T$ if for each sentence $\varphi$, either $\varphi \in T$
or $\neg \varphi \in T$.\\ or $\neg \varphi \in T$.\\
\textbf{Lemma.} A theory $T$ is complete if and only if $T$ is \textbf{Lemma.} A theory $T$ is complete if and only if $T$ is
maximally consistent. That is, $T$ is complete if and only if for maximally consistent. That is, $T$ is complete if and only if for
each sentence $\varphi$, $\varphi \not \in T$ only if each sentence $\varphi$, $\varphi \not \in T$ only if
$T \cup \lbrace \varphi \rbrace$ is inconsistent.\\ $T \cup \lbrace \varphi \rbrace$ is inconsistent.\\
\textbf{Theorem. (Tarski)} Every consistent theory $T$ is included \textbf{Theorem. (Tarski)} Every consistent theory $T$ is included
in a complete theory. in a complete theory.
\textbf{Proof :} Use Zorn's lemma on the set of consistent \textbf{Proof :} Use Zorn's lemma on the set of consistent
theories that include $T$.\\ theories that include $T$.\\
\textbf{Remark}. A theory $T$ is \emph{axiomatizable} if and only \textbf{Remark}. A theory $T$ is \emph{axiomatizable} if and only
if $T$ includes a \PMlinkname{decidable}{DecidableSet} subset $\Delta$ such that $\Delta if $T$ includes a decidable subset $\Delta$ such that $\Delta
\models T$ (every sentence of $T$ is a logical consequence of \models T$ (every sentence of $T$ is a logical consequence of
$\Delta$). Every complete axiomatizable theory $T$ is decidable; $\Delta$). Every complete axiomatizable theory $T$ is decidable;
that is, there is an algorithm that given a sentence $\varphi$ as that is, there is an algorithm that given a sentence $\varphi$ as
input yields $0$ if $\varphi \in T$, and $1$ otherwise. input yields $0$ if $\varphi \in T$, and $1$ otherwise.