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Viewing Version 5 of 'Green's theorem'
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Title of object: Green's theorem
Canonical Name: GreensTheorem
Type: Theorem

Created on: 2002-02-02 21:51:16
Modified on: 2004-04-30 11:33:08

Creator: mathcam
Modifier: mathcam
Author: mathcam
Author: slider142

Classification: msc:26B20
Keywords: path integrals, evaluating path integrals, curl of a vector field

Revision comment (for changes between this and next version):

Changes for correction #3969 ('broken').

Preamble:

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Content:

Green's theorem provides a connection between path integrals over a well-connected region in the plane and the area of the region bounded in the plane. Given a closed path $P$ bounding a region $R$ with area $A$, and a vector-valued function $\vec{F}=(f(x,y),g(x,y))$ over the plane,
$$\oint_P\vec{F}\cdot d\vec{x} = \int\!\!\!\int_{\!\!R} [g_1(x,y) - f_2(x,y)] dA$$
where $a_n$ is the derivative of $a$ with respect to the $n$th variable.
\begin{center}
\includegraphics[width=2.694444in]{greensthm}
\end{center}
\paragraph{Corollary:}
The closed path integral over a gradient of a function with continuous partial derivatives is always zero. Thus, gradients are conservative vector fields. The smooth function is called the potential of the vector field.
\paragraph{Proof:}
The corollary states that
$$\oint_P\vec{\nabla}_h\cdot d\vec{x} = 0$$
We can easily prove this using Green's theorem.
$$\oint_P\vec{\nabla}_h\cdot d\vec{x} = \int\!\!\!\int_{\!\!R} [g_1(x,y) - f_2(x,y)] dA$$
But since this is a gradient...
$$\int\!\!\!\int_{\!\!R} [g_1(x,y) - f_2(x,y)] dA = \int\!\!\!\int_{\!\!R} [h_{21}(x,y) - h_{12}(x,y)] dA$$
Since $h_{12}=h_{21}$ for any function with continuous partials, the corollary is proven.