PlanetMath (more info)
 Math for the people, by the people. Sponsor PlanetMath
Encyclopedia | Requests | Forums | Docs | Wiki | Random | RSS  
Login
create new user
name:
pass:
forget your password?
Main Menu
Viewing Version 3 of 'Barb\u{a}lat's lemma'
[ view 'Barb\u{a}lat's lemma' | back to history ]

Title of object: Barb\u{a}lat's lemma
Canonical Name: BarbualatsLemma
Type: Theorem

Created on: 2004-12-10 12:26:52
Modified on: 2005-03-05 12:12:01

Creator: jirka
Modifier: jirka
Author: jirka

Classification: msc:26A06
Synonyms: Barb\u{a}lat's lemma=Barbalat's lemma

Revision comment (for changes between this and next version):

Changes for correction #6453 ('spike function').

Preamble:

% this is the default PlanetMath preamble. as your knowledge
% of TeX increases, you will probably want to edit this, but
% it should be fine as is for beginners.

% almost certainly you want these
\usepackage{amssymb}
\usepackage{amsmath}
\usepackage{amsfonts}

% used for TeXing text within eps files
%\usepackage{psfrag}
% need this for including graphics (\includegraphics)
%\usepackage{graphicx}
% for neatly defining theorems and propositions
\usepackage{amsthm}
% making logically defined graphics
%\usepackage{xypic}

% there are many more packages, add them here as you need them

% define commands here
\theoremstyle{theorem}
\newtheorem*{thm}{Theorem}
\newtheorem*{lemma}{Lemma}
\newtheorem*{conj}{Conjecture}
\newtheorem*{cor}{Corollary}
\theoremstyle{definition}
\newtheorem*{defn}{Definition}
Content:

\begin{lemma}[Barb\u{a}lat]
Let $f \colon (0,\infty) \to {\mathbb{R}}$ be Riemann integrable and uniformly continuous then
\begin{equation*}
\lim_{t \to \infty} f(t) = 0 .
\end{equation*}
\end{lemma}

Note that if $f$ is non-negative, then Riemann integrability is the same as being $L^1$ in the sense of Lebesgue, but if $f$ oscillates then the Lebesgue integral may not exist.

Further note that the uniform continuity is required to prevent sharp ``spikes'' that might prevent the limit from existing. For example suppose we add a spike of height 1 and area $2^{-n}$ at every integer. Then the function is $L^1$, but
$f(t)$ would not have a limit at infinity.

\begin{thebibliography}{9}
\bibitem{LoRy}
Hartmut Logemann, Eugene P.\@ Ryan.
\PMlinkescapetext{Asymptotic behaviour of nonlinear systems}.
\emph{The American Mathematical Monthly}, 111(10):864--889,
2004.
\end{thebibliography}