PlanetMath (more info)
 Math for the people, by the people. Sponsor PlanetMath
Encyclopedia | Requests | Forums | Docs | Wiki | Random | RSS  
Login
create new user
name:
pass:
forget your password?
Main Menu
Viewing Version 3 of 'factorial base representation of fractions'
[ view 'factorial base representation of fractions' | back to history ]

Title of object: factorial base representation of fractions
Canonical Name: FactorialBaseRepresentationOfFractions
Type: Definition

Created on: 2007-02-26 10:58:14
Modified on: 2007-02-26 14:23:41

Creator: rspuzio
Modifier: rspuzio
Author: rspuzio

Classification: msc:11A63

Preamble:

% this is the default PlanetMath preamble. as your knowledge
% of TeX increases, you will probably want to edit this, but
% it should be fine as is for beginners.

% almost certainly you want these
\usepackage{amssymb}
\usepackage{amsmath}
\usepackage{amsfonts}

% used for TeXing text within eps files
%\usepackage{psfrag}
% need this for including graphics (\includegraphics)
%\usepackage{graphicx}
% for neatly defining theorems and propositions
%\usepackage{amsthm}
% making logically defined graphics
%\usepackage{xypic}

% there are many more packages, add them here as you need them

% define commands here
Content:

One can represent fractions as well as whole numbers using factorials
much in the same way that one has, say, a decimal representation of
both whole numbers and fractions.

Suppose that $x$ is a rational number. For simplicity, let us assume
that $0 < x < 1$. Then we can write
\[x = \sum_{k=2}^N {d_k \over k!}\]
where $0 \le d_k < k$ for some integer $N$. Unlike decimal representations
of fractions and, more generally representations with any fixed base,
factorial base representations of rational numbers all terminate.

Let us illustrate with some simple examples:
\begin{eqnarray*}
\frac{1}{2} &=& \frac{1}{2!} \\
\frac{1}{3} &=& \frac{2}{3!} \\
\frac{2}{3} &=& \frac{1}{2!} + \frac{1}{3!} \\
\frac{1}{4} &=& \frac{1}{3!} + \frac{2}{4!} \\
\frac{3}{4} &=& \frac{1}{2!} + \frac{1}{3!} + \frac{2}{4!} \\
\frac{1}{5} &=& \frac{1}{3!} + \frac{1}{4!} + \frac{1}{5!} \\
\frac{2}{5} &=& \frac{2}{3!} + \frac{1}{4!} + \frac{3}{5!} \\
\frac{3}{5} &=& \frac{1}{2!} + \frac{2}{4!} + \frac{2}{5!} \\
\frac{4}{5} &=& \frac{1}{2!} + \frac{1}{3!} + \frac{3}{4!) +
\frac{1}{5!}
\end{eqnarray*}