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Revision difference : convolution
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Let $\Sigma$ be an alphabet, $\#$ a symbol not in $\Sigma$. Let $\Sigma$ be an alphabet, $\#$ a symbol not in $\Sigma$.
Let $x_1x_2\ldots x_{|x|},y_1y_2\ldots y_{|y|},z_1z_2\ldots z_{|z|},\ldots$ be $n$ words over $\Sigma^*$. Let $l$ denote the maximum length. Let $x_1x_2\ldots x_{|x|},y_1y_2\ldots y_{|y|},z_1z_2\ldots z_{|z|},\ldots$ be $n$ words over $\Sigma^*$. Let $l$ denote the maximum length.
The \emph{convolution} of these words is The \emph{convolution} of these words is
$$(x_1,y_1,\ldots)(x_2,y_2,\ldots)\ldots(x_l,y_l,\ldots)$$where for any index greater than the length of the word, the symbol is $\#$. This is a new word in $((\Sigma\cup\{\#\})^n)^*$. $$(x_1,y_1,\ldots)(x_2,y_2,\ldots)\ldots(x_l,y_l,\ldots)$$where for any index greater than the length of the word, the symbol is $\#$. This is a new word in $((\Sigma\cup\{\#\})^n)^*$.
The convolution of $x,y,z,\ldots$ is sometimes denoted conv($x,y,z,\ldots$), or $x\star y\star z\star\ldots$ The convolution of $x,y,z,\ldots$ is sometimes denoted conv($x,y,z,\ldots$), or $x\star y\star z\star\ldots$
\subsection*{Example} \subsection*{Example}
The convolution of $and, fish, be$ is The convolution of $and, fish, be$ is
$$(a,f,b)(n,i,e)(d,s,\#)(\#,h,\#)$$ $$(a,f,b)(n,i,e)(d,s,\#)(\#,h,\#)$$
\subsection*{Notes} \subsection*{Notes}
This definition bears no \PMlinkescapetext{mathematical relation} to the notion of \PMlinkname{convolution}{Convolution} of functions. This definition bears no real relation to the notion of convolution of functions.