Chinese remainder theorem for rings, noncommutative case
Theorem 1.
(Chinese Remainder Theorem![]()
) Let be a ring and pairwise comaximal (http://planetmath.org/Comaximal) ideals such that for all . The homomorphism
![]()
:
is surjective and .
Proof.
Clearly is a homomorphism with kernel . It remains to show the surjectivity.
We have:
Moreover,
Continuing, we obtain that . We show similarly that:
Given elements , we can find and such that .
Take .
Hence
and we conclude that is surjective as required.∎
Notes 1.The relation![]()
is satisfied when is ring with unity. In that case .
2. The Chinese Remainder Theorem (http://planetmath.org/ChineseRemainderTheorem) case for integers is obtained from the above result. For this, take and . The fact that two solutions of the set of congruences![]()
must is a consequence of:
| Title | Chinese remainder theorem for rings, noncommutative case |
|---|---|
| Canonical name | ChineseRemainderTheoremForRingsNoncommutativeCase |
| Date of creation | 2013-03-22 16:53:45 |
| Last modified on | 2013-03-22 16:53:45 |
| Owner | polarbear (3475) |
| Last modified by | polarbear (3475) |
| Numerical id | 16 |
| Author | polarbear (3475) |
| Entry type | Theorem |
| Classification | msc 13A15 |
| Classification | msc 11D79 |
| Synonym | chinese remainder theorem |