derivative of even/odd function (proof)


Suppose f⁢(x)=±f⁢(-x). We need to show that f′⁢(x)=∓f′⁢(-x). To do this, let us define the auxiliary function m:ℝ→ℝ, m⁢(x)=-x. The condition on f is then f⁢(x)=±(f∘m)⁢(x). Using the chain ruleMathworldPlanetmath, we have that

f′⁢(x) = ±(f∘m)′⁢(x)
= ±f′⁢(m⁢(x))⁢m′⁢(x)
= ∓f′⁢(-x),

and the claim follows. □

Title derivative of even/odd functionMathworldPlanetmath (proof)
Canonical name DerivativeOfEvenoddFunctionproof
Date of creation 2013-03-22 13:37:57
Last modified on 2013-03-22 13:37:57
Owner mathcam (2727)
Last modified by mathcam (2727)
Numerical id 5
Author mathcam (2727)
Entry type Proof
Classification msc 26A06