Definition 1.
Let be a stationary set. Then the combinatorial principle holds if and only if there is a sequence such that each and for any , is stationary.
To get some sense of what this means, observe that for any , , so the set of is stationary (in ). More strongly, suppose . Then any subset of is bounded in so on a stationary set. Since , it follows that . Hence , the most common form (often written as just ), implies CH.
C. Akemann and N. Weaver used to construct a -algebra serving as a counterexample to Naimark’s problem.
References
- 1 Akemann, C., and N. Weaver, Consistency of a counterexample to Naimark’s problem. Preprint available on the arXiv at http://arxiv.org/abs/math.OA/0312135http://arxiv.org/abs/math.OA/0312135.
| Title | |
|---|---|
| Canonical name | Diamond |
| Date of creation | 2013-03-22 12:53:49 |
| Last modified on | 2013-03-22 12:53:49 |
| Owner | Henry (455) |
| Last modified by | Henry (455) |
| Numerical id | 8 |
| Author | Henry (455) |
| Entry type | Definition |
| Classification | msc 03E65 |
| Synonym | diamond |
| Related topic | Clubsuit |
| Related topic | DiamondIsEquivalentToClubsuitAndContinuumHypothesis |
| Related topic | ProofOfDiamondIsEquivalentToClubsuitAndContinuumHypothesis |
| Related topic | CombinatorialPrinciple |
| Defines |