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# eigenvalues of a Hermitian matrix are real

The eigenvalues of a Hermitian (or self-adjoint) matrix are real.

###### Proof.

Suppose $\lambda$ is an eigenvalue of the self-adjoint matrix $A$ with non-zero eigenvector $v$. Then $Av=\lambda v$.

$\lambda^{{\ast}}v^{{H}}v=\left(\lambda v\right)^{{H}}v=\left(Av\right)^{{H}}v=% v^{{H}}A^{{H}}v=v^{{H}}Av=v^{{H}}\lambda v=\lambda v^{{H}}v$ |

Since $v$ is non-zero by assumption, $v^{H}v$ is non-zero as well and so $\lambda^{{*}}=\lambda$, meaning that $\lambda$ is real. ∎

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Reference

Type of Math Object:

Theorem

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## Mathematics Subject Classification

15A57*no label found*

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