example of a strictly increasing quasisymmetric singular function


An example of a strictly increasing quasisymmetric function that also a purely singular function can be defined as:

f(x)=limk0xi=1k(1+λcosnis)ds,

where 0<λ<1 and carefully picked ni. We can pick the ni such that ni+1 is strictly greater then j=1inj. However if we pick the λ and ni more carefully, we can construct functions with the quasisymmetricity constant as close to 1 as we want. That is, we can construct functions such that

1Mf(x+t)-f(x)f(x)-f(x-t)M

for all x and t where M is as close to 1 as we want. If M=1 note that the function must be a straight line.

It is also possible from this to construct a quasiconformal mapping of the upper half plane to itself by extending this function to the whole real line and then using the Beurling-Ahlfors quasiconformal extension. Then we’d have a quasiconformal mapping such that its boundary correspondence would be a purely singular function.

For more detailed explanation, and proof (it is too long to reproduce here) see bibliography.

Bibliography

  • A. Beurling, L. V. Ahlfors. . Acta Math., 96:125-142, 1956.

  • J. Lebl. . . Also available at http://www.jirka.org/thesis.pdfhttp://www.jirka.org/thesis.pdf

Title example of a strictly increasing quasisymmetric singular function
Canonical name ExampleOfAStrictlyIncreasingQuasisymmetricSingularFunction
Date of creation 2013-03-22 14:10:37
Last modified on 2013-03-22 14:10:37
Owner jirka (4157)
Last modified by jirka (4157)
Numerical id 5
Author jirka (4157)
Entry type Example
Classification msc 26A30