finite dimensional modules over algebra
Assume that is a field, is a -algebra and is a -module over . In particular is a -module and a vector space over , thus we may speak about being finitely generated as -module and finite dimensional as a vector space. These two concepts are related as follows:
Proposition. Assume that and are both unital and additionaly is finite dimensional. Then is finite dimensional vector space if and only if is finitely generated -module.
Proof. ,,” Of course if is finite dimensional, then there exists basis
Thus every element of can be (uniquely) expressed in the form
which is equal to
since and are unital. This completes this implication, because for all .
,,” Assume that is finitely generated -module. In particular there is a subset
such that every element of is of the form
with all . Let be with the decomposition as above. Now is finite dimensional, so there is a subset
which is a -basis of . In particular for each we have
with . Thus we obtain
which shows, that all together make a set of generators of over (note that and are independent on ). Since it is finite, then is finite dimensional and the proof is complete.
Title | finite dimensional modules over algebra |
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Canonical name | FiniteDimensionalModulesOverAlgebra |
Date of creation | 2013-03-22 19:16:35 |
Last modified on | 2013-03-22 19:16:35 |
Owner | joking (16130) |
Last modified by | joking (16130) |
Numerical id | 4 |
Author | joking (16130) |
Entry type | Definition |
Classification | msc 16S99 |
Classification | msc 20C99 |
Classification | msc 13B99 |