Galois groups of finite abelian extensions of
Theorem.
Let be a finite abelian group with . Then there exist infinitely many number fields![]()
with Galois and .
Proof.
This will first be proven for cyclic.
Let . By Dirichlet’s theorem on primes in arithmetic progressions, there exists a prime with . Let denote a root of unity![]()
. Let . Then is Galois with cyclic of order (http://planetmath.org/OrderGroup) . Since divides , there exists a subgroup
![]()
of such that . Since is cyclic, it is abelian
![]()
, and is a normal subgroup
![]()
of . Let , the subfield
![]()
of fixed (http://planetmath.org/FixedField) by . Then is Galois with cyclic of order . Thus, .
Let and be distinct primes with and . Then there exist subfields and of and , respectively, such that and . Note that since . Thus, . Therefore, for every prime with , there exists a distinct number field such that is Galois and . The theorem in the cyclic case follows from using the full of Dirichlet’s theorem on primes in arithmetic progressions: There exist infinitely many primes with .
The general case follows immediately from the above , the fundamental theorem of finite abelian groups (http://planetmath.org/FundamentalTheoremOfFinitelyGeneratedAbelianGroups), and a theorem regarding the Galois group![]()
of the compositum of two Galois extensions
![]()
.
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| Title | Galois groups of finite abelian extensions |
|---|---|
| Canonical name | GaloisGroupsOfFiniteAbelianExtensionsOfmathbbQ |
| Date of creation | 2013-03-22 16:18:40 |
| Last modified on | 2013-03-22 16:18:40 |
| Owner | Wkbj79 (1863) |
| Last modified by | Wkbj79 (1863) |
| Numerical id | 11 |
| Author | Wkbj79 (1863) |
| Entry type | Theorem |
| Classification | msc 11R32 |
| Classification | msc 11N13 |
| Classification | msc 11R20 |
| Classification | msc 12F10 |
| Related topic | AbelianNumberField |