isomorphism swapping zero and unity
Then we see that
| (2) |
But moreover, the algebraic system is a unitary ring, too, and isomorphic with the original ring.
In fact, we may define the bijective![]()
mapping
| (3) |
from to and verify that it is homomorphic:
Thus as a homomorphic image (http://planetmath.org/HomomorphicImageOfGroup) of the ring is a ring, it’s a question of two isomorphic rings.
| Title | isomorphism swapping zero and unity |
| Canonical name | IsomorphismSwappingZeroAndUnity |
| Date of creation | 2013-03-22 19:17:16 |
| Last modified on | 2013-03-22 19:17:16 |
| Owner | pahio (2872) |
| Last modified by | pahio (2872) |
| Numerical id | 7 |
| Author | pahio (2872) |
| Entry type | Example |
| Classification | msc 16B99 |
| Classification | msc 20A05 |
| Classification | msc 16S50 |
| Related topic | RingHomomorphism |
| Related topic | EpimorphismBetweenUnitaryRings |
| Related topic | Null |
| Related topic | TranslationAutomorphismOfAPolynomialRing |