isomorphism swapping zero and unity


Let  (R,+,⋅)  be a ring with unity 1.  Define two new binary operationsMathworldPlanetmath of R as follows:

a⊕b=:a+b-1,a⊙b=:a+b-a⋅b (1)

Then we see that

a⊕1=a= 1⊕a,a⊙0=a= 0⊙a. (2)

But moreover, the algebraic system  (R,⊕,⊙)  is a unitary ring, too, and isomorphicPlanetmathPlanetmathPlanetmath with the original ring.

In fact, we may define the bijectiveMathworldPlanetmathPlanetmath mapping

f:x↦ 1-x (3)

from R to R and verify that it is homomorphic:

f⁢(a)⊕f⁢(b)=(1-a)⊕(1-b)=(1-a)+(1-b)-1= 1-a-b=f⁢(a+b),
f⁢(a)⊙f⁢(b)=(1-a)⊙(1-b)=(1-a)+(1-b)-(1-a)⋅(1-b)= 1-a⋅b=f⁢(a⋅b)

Thus  (R,⊕,⊙)  as a homomorphic imagePlanetmathPlanetmathPlanetmath (http://planetmath.org/HomomorphicImageOfGroup) of the ring  (R,+,⋅)  is a ring, it’s a question of two isomorphic rings.

Title isomorphism swapping zero and unity
Canonical name IsomorphismSwappingZeroAndUnity
Date of creation 2013-03-22 19:17:16
Last modified on 2013-03-22 19:17:16
Owner pahio (2872)
Last modified by pahio (2872)
Numerical id 7
Author pahio (2872)
Entry type Example
Classification msc 16B99
Classification msc 20A05
Classification msc 16S50
Related topic RingHomomorphism
Related topic EpimorphismBetweenUnitaryRings
Related topic Null
Related topic TranslationAutomorphismOfAPolynomialRing