Martin’s axiom and the continuum hypothesis
always holds
Given a countable collection of dense subsets of a partial order, we can selected a set such that is in the -th dense subset, and for each . Therefore implies .
If then , and in fact
, so , hence it will suffice to find an surjective function from to .
Let , a sequence of infinite subsets of such that for any , is finite.
Given any subset we will construct a function such that a unique can be recovered from each . will have the property that if then for finitely many elements , and if then for infinitely many elements of .
Let be the partial order (under inclusion) such that each element satisfies:
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is a partial function from to
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There exist such that for each ,
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There is a finite subset of , , such that
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For each , for finitely many elements of
This satisfies ccc. To see this, consider any uncountable sequence of elements of . There are only countably many finite subsets of , so there is some such that for uncountably many and is the same for each such element. Since each of these function’s domain covers only a finite number of the , and is on all but a finite number of elements in each, there are only a countable number of different combinations available, and therefore two of them are compatible.
Consider the following groups of dense subsets:
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for . This is obviously dense since any not already in can be extended to one which is by adding
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for . This is dense since if then is.
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For each , , for some . This is dense since if then . But is finite, and the intersection of with any other is finite, so this intersection is finite, and hence bounded by some . is infinite, so there is some . So .
By , given any set of dense subsets of , there is a generic which intersects all of them. There are a total of dense subsets in these three groups, and hence some generic intersecting all of them. Since is directed, is a partial function from to . Since for each , is non-empty, , so is a total function. Since for is non-empty, there is some element of whose domain contains all of and is on a finite number of them, hence for a finite number of . Finally, since for each , , the set of such that is unbounded, and hence infinite. So is as promised, and .
Title | Martin’s axiom and the continuum hypothesis |
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Canonical name | MartinsAxiomAndTheContinuumHypothesis |
Date of creation | 2013-03-22 12:55:05 |
Last modified on | 2013-03-22 12:55:05 |
Owner | Henry (455) |
Last modified by | Henry (455) |
Numerical id | 4 |
Author | Henry (455) |
Entry type | Result |
Classification | msc 03E50 |