nets and closures of subspaces
Theorem.
A point of a topological space is in the closure of a subspace if and only if there is a net of points of the subspace converging to the point.
Proof.
Let be a topological space, a point of , and a subspace of . Suppose first that , and let be the collection of neighborhoods of , http://planetmath.org/node/123partially ordered by reverse . For each , select a point (such a point is guaranteed to exist because ); then is a net of points in , and we claim that . To see this, let be a neighborhood of in , and note that, by construction, ; furthermore, if satisfies , then because , . It follows that . Conversely, suppose there exists a net of points of converging to , and let be a neighborhood of . Since , there exists such that whenever . Because for each by hypothesis, we may conclude that , hence that . â
The forward implication of the preceding is a generalization of the result that a point of a topological space is in the closure of a subspace if there is a sequence of points of the subspace converging to the point, as a sequence is just a net with the positive integers as its http://planetmath.org/node/360domain; however, the converse (if a point is in the closure of a subspace then there exists a sequence of points of the subspace converging to the point) requires the additional condition that the ambient topological space be first countable.
Title | nets and closures of subspaces |
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Canonical name | NetsAndClosuresOfSubspaces |
Date of creation | 2013-03-22 17:18:34 |
Last modified on | 2013-03-22 17:18:34 |
Owner | azdbacks4234 (14155) |
Last modified by | azdbacks4234 (14155) |
Numerical id | 11 |
Author | azdbacks4234 (14155) |
Entry type | Theorem |
Classification | msc 54A20 |
Related topic | Net |
Related topic | DirectedSet |
Related topic | PartialOrder |