nets and closures of subspaces
Theorem.
A point of a topological space![]()
is in the closure
![]()
of a subspace
![]()
if and only if there is a net of points of the subspace converging to the point.
Proof.
Let be a topological space, a point of , and a subspace of .
Suppose first that , and let be the collection![]()
of neighborhoods
![]()
of , http://planetmath.org/node/123partially ordered by reverse . For each , select a point (such a point is guaranteed to exist because ); then is a net of points in , and we claim that . To see this, let be a neighborhood of in , and note that, by construction, ; furthermore, if satisfies , then because , . It follows that .
Conversely, suppose there exists a net of points of converging to , and let be a neighborhood of . Since , there exists such that whenever . Because for each by hypothesis
![]()
, we may conclude that , hence that .
â
The forward implication![]()
of the preceding is a generalization
of the result that a point of a topological space is in the closure of a subspace if there is a sequence of points of the subspace converging to the point, as a sequence is just a net with the positive integers as its http://planetmath.org/node/360domain; however, the converse (if a point is in the closure of a subspace then there exists a sequence of points of the subspace converging to the point) requires the additional condition that the ambient topological space be first countable.
| Title | nets and closures of subspaces |
|---|---|
| Canonical name | NetsAndClosuresOfSubspaces |
| Date of creation | 2013-03-22 17:18:34 |
| Last modified on | 2013-03-22 17:18:34 |
| Owner | azdbacks4234 (14155) |
| Last modified by | azdbacks4234 (14155) |
| Numerical id | 11 |
| Author | azdbacks4234 (14155) |
| Entry type | Theorem |
| Classification | msc 54A20 |
| Related topic | Net |
| Related topic | DirectedSet |
| Related topic | PartialOrder |