proof of parallelogram law
The proof follows directly from Apollonius theorem![]()
noticing that each diagonal
is a median for the triangles in which parallelogram
![]()
is split by the other diagonal.
Also, the diagonals bisect each other.
Therefore, Apollonius theorem implies
Multiplying both sides by and simplification leads to the desired expression.
| Title | proof of parallelogram law |
|---|---|
| Canonical name | ProofOfParallelogramLaw |
| Date of creation | 2013-03-22 12:41:29 |
| Last modified on | 2013-03-22 12:41:29 |
| Owner | Mathprof (13753) |
| Last modified by | Mathprof (13753) |
| Numerical id | 5 |
| Author | Mathprof (13753) |
| Entry type | Proof |
| Classification | msc 51-00 |
| Related topic | ApolloniusTheorem |
| Related topic | Median |
| Related topic | ProofOfParallelogramLaw2 |