proof of ratio test
Assume . By definition such that
i.e. eventually the series becomes less than a convergent geometric series, therefore a shifted subsequence of converges by the comparison test. Note that a general sequence converges iff a shifted subsequence of converges. Therefore, by the absolute convergence theorem, the series converges.
Similarly for a shifted subsequence of becomes greater than a geometric series tending to , and so also tends to . Therefore diverges.
Title | proof of ratio test |
---|---|
Canonical name | ProofOfRatioTest |
Date of creation | 2013-03-22 12:24:46 |
Last modified on | 2013-03-22 12:24:46 |
Owner | vitriol (148) |
Last modified by | vitriol (148) |
Numerical id | 6 |
Author | vitriol (148) |
Entry type | Proof |
Classification | msc 40A05 |
Classification | msc 26A06 |