# sines law

Sines Law.

Let $ABC$ be a triangle where $a,b,c$ are the sides opposite to $A,B,C$ respectively, and let $R$ be the radius of the circumcircle^{}. Then the following relation holds:

$$\frac{a}{\mathrm{sin}A}=\frac{b}{\mathrm{sin}B}=\frac{c}{\mathrm{sin}C}=2R.$$ |

Title | sines law |
---|---|

Canonical name | SinesLaw |

Date of creation | 2013-03-22 11:42:40 |

Last modified on | 2013-03-22 11:42:40 |

Owner | drini (3) |

Last modified by | drini (3) |

Numerical id | 26 |

Author | drini (3) |

Entry type | Theorem |

Classification | msc 51-00 |

Classification | msc 97-01 |

Synonym | law of sines |

Related topic | CosinesLaw |

Related topic | SinesLawProof |

Related topic | Triangle |