# tangents law

Let $ABC$ be a triangle with $a,b$ and $c$ being the sides opposite to $A,B$ and $C$ respectively. Then the following relation holds.

 $\frac{a-b}{a+b}=\frac{\tan(\frac{A-B}{2})}{\tan(\frac{A+B}{2})}.$
Title tangents law TangentsLaw 2013-03-22 13:11:01 2013-03-22 13:11:01 giri (919) giri (919) 5 giri (919) Theorem msc 51-00 law of tangents