uniqueness conjecture for Markov numbers
Conjecture. Given a Markov number , there are several other Markov numbers and such that , but there is only set of values of and satisfying the inequality .
The conjecture is easy enough to check for small values. For example, for , we could even test and we know not to be Markov numbers with minimum increase in computational overhead. Trying the triples in order: (1, 1, 5), (1, 2, 5), (1, 3, 5), (1, 4, 5), (2, 1, 5), … (4, 4, 5) against we obtain the sequence , 0, 10, 18, 0, 27, 52, 75, 10, 52, 92, 130, 18, 75, 130, 183. It doesn’t take significantly larger Markov numbers to show the need for a general proof of uniqueness. Many attempted proofs have been submitted, but Richard Guy dismisses them all as seemingly faulty.
A divide-and-conquer approach to the problem has yielded encouraging results, however. Baragar proved the uniqueness of prime Markov numbers as well as semiprimes . Schmutz then proved the uniqueness of Markov numbers of the forms and . Ying Zhang used these results to extend this to and .
References
- 1 R. K. Guy, Unsolved Problems in Number Theory New York: Springer-Verlag 2004: D12
- 2 Ying Zhang, “Congruence and Uniqueness of Certain Markov Numbers” Acta Arithmetica 128 3 (2007): 297
Title | uniqueness conjecture for Markov numbers |
---|---|
Canonical name | UniquenessConjectureForMarkovNumbers |
Date of creation | 2013-03-22 17:26:16 |
Last modified on | 2013-03-22 17:26:16 |
Owner | PrimeFan (13766) |
Last modified by | PrimeFan (13766) |
Numerical id | 5 |
Author | PrimeFan (13766) |
Entry type | Conjecture |
Classification | msc 11J06 |
Synonym | unicity conjecture for Markov numbers |