characterization of tight frames in ℝn


Question 1.

What conditions must the vectors {xi}i=1k⊂Rn satisfy in order to be a tight frame in Rn?

Solution.

Let E be the k×n matrix whose rows are the vectors {xi}i=1k:

E=(xi,1⋯xi,n⋮⋱⋮xk,1⋯xk,n).

Then the tight frame condition ∑i=1k|⟨x,xi⟩|2=A⁢∥x∥2 gives (E⁢x)T⁢E⁢x=A⁢xT⁢x for all x∈ℝn, or ET⁢E=A⁢In:

ET⁢E=(∑i=1kxi,1⁢xi,1⋯∑i=1kxi,1⁢xi,k⋮⋱⋮∑i=1kxi,k⁢xi,1⋯∑i=1kxi,k⁢xi,k)=(A⋯⁢0⁢⋯0⋮⋱⋮0⋯⁢0⁢⋯A)=A⁢In.

Therefore, the vectors

{xi=(xi,1⋮xi,n)}i=1k⊂ℝn

are an A-tight frame iff the vectors

{xi′=(x1,i⋮xk,i)}i=1n⊂ℝk,

i.e., the columns of E, are all of norm A and form an orthogonalMathworldPlanetmathPlanetmath family.

Title characterizationMathworldPlanetmath of tight frames in ℝn
Canonical name CharacterizationOfTightFramesInmathbbRn
Date of creation 2013-03-22 14:27:08
Last modified on 2013-03-22 14:27:08
Owner swiftset (1337)
Last modified by swiftset (1337)
Numerical id 5
Author swiftset (1337)
Entry type Result
Classification msc 46C99