converging alternating series not satisfying all Leibniz’ conditions
| (1) |
satisfies the other requirements of Leibniz test except the monotonicity of the absolute values![]()
of the terms. The convergence may however be shown by manipulating the terms as follows.
We first multiply the numerator and the denominator of the general term by the difference , getting from (1)
| (2) |
One can that the series
| (3) |
satisfies all requirements of Leibniz test and thus is convergent![]()
. Since
and the over-harmonic series converges, the comparison test![]()
guarantees the convergence of the series
| (4) |
Therefore the difference series of (3) and (4) and consequently, by (2), the given series (1) is convergent.
| Title | converging alternating series not satisfying all Leibniz’ conditions |
|---|---|
| Canonical name | ConvergingAlternatingSeriesNotSatisfyingAllLeibnizConditions |
| Date of creation | 2013-03-22 19:00:45 |
| Last modified on | 2013-03-22 19:00:45 |
| Owner | pahio (2872) |
| Last modified by | pahio (2872) |
| Numerical id | 7 |
| Author | pahio (2872) |
| Entry type | Example |
| Classification | msc 40-00 |
| Classification | msc 40A05 |
| Related topic | SumOfSeriesDependsOnOrder |
| Related topic | LeibnizEstimateForAlternatingSeries |