derivative of even/odd function (proof)
Suppose f(x)=±f(-x). We need to show that
f′(x)=∓f′(-x).
To do this, let us define the auxiliary function
m:ℝ→ℝ, m(x)=-x.
The condition on f is then f(x)=±(f∘m)(x).
Using the chain rule, we have that
f′(x) | = | ±(f∘m)′(x) | ||
= | ±f′(m(x))m′(x) | |||
= | ∓f′(-x), |
and the claim follows. □
Title | derivative of even/odd function![]() |
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Canonical name | DerivativeOfEvenoddFunctionproof |
Date of creation | 2013-03-22 13:37:57 |
Last modified on | 2013-03-22 13:37:57 |
Owner | mathcam (2727) |
Last modified by | mathcam (2727) |
Numerical id | 5 |
Author | mathcam (2727) |
Entry type | Proof |
Classification | msc 26A06 |