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$(1+\frac{\alpha}{n})^n$ is monotone for large $n$ (Theorem)
Lemma 1   Let $ \alpha$ be a real number. The sequence $ (1+\frac{\alpha}{n})^n$ is monotone increasing for all $ n> \vert\alpha\vert$.
Proof. Let $ n>\vert\alpha\vert$. We want to prove the following inequality:
$\displaystyle \left(1+\frac{\alpha}{n}\right)^n \leq \left(1+\frac{\alpha}{n+1}\right)^{n+1} $
Since both sides are positive, this follows by taking the $ (n+1)$-th root and using the arithmetic-geometric-harmonic means inequality:
$\displaystyle \sqrt[n+1]{\left(1+\frac{\alpha}{n}\right)^n} = \underbrace{\sqrt... ...} } \leq \frac{1+n\left(1+\frac{\alpha}{n}\right)}{n+1} = 1+\frac{\alpha}{n+1} $
$ \qedsymbol$



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Cross-references: arithmetic-geometric-harmonic means inequality, root, positive, sides, inequality, monotone increasing, sequence, real number

This is version 1 of $(1+\frac{\alpha}{n})^n$ is monotone for large $n$, born on 2008-03-12.
Object id is 10389, canonical name is 1fracalphannIsMonotoneForLargeN.
Accessed 280 times total.

Classification:
AMS MSC40-01 (Sequences, series, summability :: Instructional exposition )
 00-01 (General :: Instructional exposition )

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