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[parent] consequence operator determined by a class of subsets (Theorem)
Theorem 1   Let $ L$ be a set and let $ K$ be a subset of $ \mathcal{P}(L)$. The the mapping $ C \colon \mathcal{P}(L) \to \mathcal{P}(L)$ defined as $ C(X) = \cap \{ Y \in K \mid X \subseteq Y\}$ is a consequence operator.
Proof. We need to check that $ C$ satisfies the defining properties.

Property 1: Since every element of the set $ \{ Y \in K \mid X \subseteq Y \}$ contains $ X$, we have $ X \subseteq C(X)$.

Property 2: For every element $ Y$ of $ K$ such that $ X \subseteq Y$, it also is the case that $ C(X) \subseteq Y$ because an intersection of a family of sets is a subset of any member of the family. In other words (or rather, symbols),

$\displaystyle \{ Y \in K \mid X \subseteq Y \} \subseteq \{ Y \in K \mid C(X) \subseteq Y \},$
hence $ C(C(X)) \subseteq C(X)$. By the first property proven above, $ C(X) \subseteq C(C(X))$ so $ C(C(X)) = C(X)$. Thus, $ C \circ C = C$.

Property 3: Let $ X$ and $ Y$ be two subsets of $ L$ such that $ X \subseteq Y$. Then if, for some other subset $ Z$ of $ L$, we have $ Y \subset Z$, it follows that $ X \subset Z$. Hence,

$\displaystyle \{ Z \in K \mid Y \subseteq Z \} \subseteq \{ Z \in K \mid X \subseteq Z \},$
so $ C(X) \subseteq C(Y)$.

$ \qedsymbol$



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Cross-references: intersection, contains, property, defining properties, satisfies, consequence operator, mapping, subset
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This is version 7 of consequence operator determined by a class of subsets, born on 2006-12-22, modified 2006-12-24.
Object id is 8671, canonical name is ConsequenceOperatorDeterminedByAClassOfSubsets.
Accessed 710 times total.

Classification:
AMS MSC03B22 (Mathematical logic and foundations :: General logic :: Abstract deductive systems)
 03G10 (Mathematical logic and foundations :: Algebraic logic :: Lattices and related structures)
 03G25 (Mathematical logic and foundations :: Algebraic logic :: Other algebras related to logic)

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