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adjoining an identity to a semigroup (Definition)

It is possible to formally adjoin an identity element to any semigroup to make it into a monoid.

Suppose $ S$ is a semigroup without an identity, and consider the set $ S \cup \{1\}$ where $ 1$ is a symbol not in $ S$. Extend the semigroup operation from $ S$ to $ S \cup \{1\}$ by additionally defining:

$\displaystyle s \cdot 1 = s = 1 \cdot s,$   for all$\displaystyle s \in S \cup {1}$
It is easy to verify that this defines a semigroup (associativity is the only thing that needs to be checked).

As a matter of notation, it is customary to write $ S^1$ for the semigroup $ S$ with an identity adjoined in this manner, if $ S$ does not already have one, and to agree that $ S^1 = S$, if $ S$ does already have an identity.

Despite the simplicity of this construction, however, it rarely allows one to simplify a problem by considering monoids instead of semigroups. As soon as one starts to look at the structure of the semigroup, it is almost invariably the case that one needs to consider subsemigroups and ideals of the semigroup which do not contain the identity.



"adjoining an identity to a semigroup" is owned by mclase.
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See Also: semigroup, monoid

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Cross-references: contain, ideals, subsemigroups, structure, associativity, operation, identity, monoid, semigroup, identity element
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This is version 2 of adjoining an identity to a semigroup, born on 2002-09-03, modified 2002-09-04.
Object id is 3410, canonical name is AdjoiningAnIdentityToASemigroup3.
Accessed 1747 times total.

Classification:
AMS MSC20M99 (Group theory and generalizations :: Semigroups :: Miscellaneous)

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