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algebraically closed (Definition)

A field $K$ is algebraically closed if every non-constant polynomial in $K[X]$ has a root in $K$

An extension field $L$ of $K$ is an algebraic closure of $K$ if $L$ is algebraically closed and every element of $L$ is algebraic over $K$ Using the axiom of choice, one can show that any field has an algebraic closure. Moreover, any two algebraic closures of a field are isomorphic as fields, but not necessarily canonically isomorphic.




"algebraically closed" is owned by djao. [ full author list (2) | owner history (1) ]
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Also defines:  algebraic closure

Attachments:
cardinality of algebraic closure (Theorem) by rspuzio
finite field cannot be algebraically closed (Theorem) by rspuzio
algebraic closure of a finite field (Derivation) by Algeboy
every algebraically closed field is perfect (Result) by polarbear
alternative definition of algebraically closed (Derivation) by polarbear
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Cross-references: isomorphic, axiom of choice, algebraic, extension field, root, polynomial, field
There are 99 references to this entry.

This is version 6 of algebraically closed, born on 2002-01-21, modified 2008-09-13.
Object id is 1509, canonical name is AlgebraicallyClosed.
Accessed 11167 times total.

Classification:
AMS MSC12F05 (Field theory and polynomials :: Field extensions :: Algebraic extensions)

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