PlanetMath (more info)
 Math for the people, by the people.
Encyclopedia | Requests | Forums | Docs | Wiki | Random | RSS  
Login
create new user
name:
pass:
forget your password?
Main Menu
Owner confidence rating: Very high Entry average rating: Very high
[parent] alternative proof that $\sqrt{2}$ is irrational (Proof)

Following is a proof that $ \sqrt{2}$ is irrational.

The polynomial $ x^2-2$ is irreducible over $ \mathbb{Z}$ by Eisenstein's criterion with $ p=2$. Thus, $ x^2-2$ is irreducible over $ \mathbb{Q}$ by Gauss's lemma. Therefore, $ x^2-2$ does not have any roots in $ \mathbb{Q}$. Since $ \sqrt{2}$ is a root of $ x^2-2$, it must be irrational.

This method generalizes to show that any number of the form $ \sqrt[r]{n}$ is not rational, where $ r \in \mathbb{Z}$ with $ r>1$ and $ n \in \mathbb{Z}$ such that there exists a prime $ p$ dividing $ n$ with $ p^2$ not dividing $ n$.



"alternative proof that $\sqrt{2}$ is irrational" is owned by Wkbj79.
(view preamble)

View style:

See Also: irrational, Eisenstein criterion, Gauss's lemma II


This object's parent.
Log in to rate this entry.
(view current ratings)

Cross-references: prime, rational, number, roots, Eisenstein's criterion, irreducible, polynomial, irrational, proof
There are 2 references to this entry.

This is version 5 of alternative proof that $\sqrt{2}$ is irrational, born on 2007-04-14, modified 2007-08-23.
Object id is 9183, canonical name is AlternativeProofThatSqrt2IsIrrational.
Accessed 1114 times total.

Classification:
AMS MSC11J72 (Number theory :: Diophantine approximation, transcendental number theory :: Irrationality; linear independence over a field)
 11J82 (Number theory :: Diophantine approximation, transcendental number theory :: Measures of irrationality and of transcendence)
 12E05 (Field theory and polynomials :: General field theory :: Polynomials )
 13A05 (Commutative rings and algebras :: General commutative ring theory :: Divisibility)

Pending Errata and Addenda
None.
[ View all 2 ]
Discussion
Style: Expand: Order:
forum policy
Imaginary irrational number? by pahio on 2007-04-15 03:49:36
Hi, are there more people thinking that non-real complex numbers (in Continental Europe: imaginary numbers) are irrational -- because they are not rational? I think such a terminology is exceptional.
Jussi
[ reply | up ]

Interact
post | correct | update request | add example | add (any)