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Bernoulli's inequality (Theorem)

Let $x$ and $r$ be real numbers. If $0>r>-1$ or $r>1$ and $x>-1$ then $$(1+x)^r\ge 1+xr.$$

The inequality also holds when $r$ is an even integer. For $0<r<1$ the inverse inequality holds.




"Bernoulli's inequality" is owned by rspuzio. [ full author list (3) | owner history (2) ]
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See Also: inequalities for differences of powers


Attachments:
proof of Bernoulli's inequality (Proof) by danielm
another proof of Bernoulli's inequality (Proof) by a4karo
proof of Bernoulli's inequality employing the mean value theorem (Proof) by rspuzio
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Cross-references: inverse, even integer, inequality, real numbers
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This is version 7 of Bernoulli's inequality, born on 2001-10-17, modified 2008-11-19.
Object id is 275, canonical name is BernoullisInequality.
Accessed 12221 times total.

Classification:
AMS MSC26D99 (Real functions :: Inequalities :: Miscellaneous)

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