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Cardano's derivation of the cubic formula
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(Proof)
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To solve the cubic polynomial equation
for , the first step is to apply the Tchirnhaus transformation
. This reduces the equation to
, where
The next step is to substitute , to obtain
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(1) |
or, with the terms collected,
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(2) |
From equation (2), we see that if and are chosen so that
and , then will satisfy equation (1), and the cubic equation will be solved!
There remains the matter of solving
and for and . From the second equation, we get
, and substituting this into the first equation yields
which is a quadratic equation in . Solving for using the quadratic formula, we get
Using these values for and , you can back-substitute , ,
, and to get the expression for the first root in the cubic formula. The second and third roots and are obtained by performing synthetic division
using , and using the quadratic formula on the remaining quadratic factor.
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"Cardano's derivation of the cubic formula" is owned by djao.
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(view preamble)
Cross-references: factor, synthetic division, root, expression, quadratic formula, quadratic equation, cubic equation, terms, transformation, equation, polynomial
There are 2 references to this entry.
This is version 8 of Cardano's derivation of the cubic formula, born on 2002-01-06, modified 2005-07-24.
Object id is 1408, canonical name is CardanosDerivationOfTheCubicFormula.
Accessed 11484 times total.
Classification:
| AMS MSC: | 12D10 (Field theory and polynomials :: Real and complex fields :: Polynomials: location of zeros ) |
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Pending Errata and Addenda
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