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characteristic subgroup
If $(G,*)$ is a group, then $H$ is a characteristic subgroup of $G$ (written $H \Char G$ ) if every automorphism of $G$ maps $H$ to itself. That is, if $f\in{\rm Aut}(G)$ and $h\in H$ then $f(h)\in H$ .
A few properties of characteristic subgroups:
- If $H\Char G$ then $H$ is a normal subgroup of $G$ .
- If $G$ has only one subgroup of a given cardinality then that subgroup is characteristic.
- If $K\Char H$ and $H\trianglelefteq G$ then $K\trianglelefteq G$ . (Contrast with normality of subgroups is not transitive.)
- If $K\Char H$ and $H\Char G$ then $K\Char G$ .
Proofs of these properties:
- Consider $H\Char G$ under the inner automorphisms of $G$ . Since every automorphism preserves $H$ , in particular every inner automorphism preserves $H$ , and therefore $g*h*g^{-1}\in H$ for any $g\in G$ and $h\in H$ . This is precisely the definition of a normal subgroup.
- Suppose $H$ is the only subgroup of $G$ of order $n$ . In general, homomorphisms take subgroups to subgroups, and of course isomorphisms take subgroups to subgroups of the same order. But since there is only one subgroup of $G$ of order $n$ , any automorphism must take $H$ to $H$ , and so $H\Char G$ .
- Take $K\Char H$ and $H\trianglelefteq G$ , and consider the inner automorphisms of $G$ (automorphisms of the form $h\mapsto g*h*g^{-1}$ for some $g\in G$ ). These all preserve $H$ , and so are automorphisms of $H$ . But any automorphism of $H$ preserves $K$ , so for any $g\in G$ and $k\in K$ , $g*k*g^{-1}\in K$ .
- Let $K\Char H$ and $H\Char G$ , and let $\phi$ be an automorphism of $G$ . Since $H\Char G$ , $\phi[H]=H$ , so $\phi_H$ , the restriction of $\phi$ to $H$ is an automorphism of $H$ . Since $K\Char H$ , so $\phi_H[K]=K$ . But $\phi_H$ is just a restriction of $\phi$ , so $\phi[K]=K$ . Hence $K\Char G$ .
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