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is not empty
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(Theorem)
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Theorem. If is a non-empty open set in
, then the set of smooth functions with compact support
is non-trivial (that is, it contains functions other than the zero function).
Remark. This theorem may seem to be obvious at first sight. A way to notice that it is not so obvious, is to formulate it for analytic functions with compact support: in that case, the result does not hold; in fact, there are no nonconstant analytic functions with compact support at all. One important consequence of this theorem is the existence of partitions of unity.
Proof of the theorem: Let us first prove this for : If be real numbers, then there exists a smooth non-negative function
, whose support is the compact set .
To see this, let
be the function defined on this page, and let
Since is smooth, it follows that is smooth. Also, from the definition of , we see that
precisely when , and
precisely when . Thus the support of is indeed .
Since is non-empty and open there exists an and
such that
. Let be smooth function such that
, and let
Since
(Euclidean norm) is smooth, the claim follows.
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" is not empty" is owned by matte. [ full author list (5) | owner history (3) ]
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(view preamble)
Cross-references: Euclidean norm, smooth function, open, compact set, smooth, real numbers, proof, existence of partitions of unity, consequence, compact, analytic functions, obvious, functions, smooth functions with compact support, open set
There is 1 reference to this entry.
This is version 14 of is not empty, born on 2003-07-05, modified 2006-05-27.
Object id is 4422, canonical name is Cinfty_0UIsNotEmpty.
Accessed 3199 times total.
Classification:
| AMS MSC: | 26B05 (Real functions :: Functions of several variables :: Continuity and differentiation questions) |
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Pending Errata and Addenda
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