PlanetMath (more info)
 Math for the people, by the people. Sponsor PlanetMath
Encyclopedia | Requests | Forums | Docs | Wiki | Random | RSS  
Login
create new user
name:
pass:
forget your password?
Main Menu
Owner confidence rating: High Entry average rating: No information on entry rating
[parent] compactly supported continuous functions are dense in $L^p$ (Theorem)

Let $(X, \mathcal{B}, \mu)$ be a measure space, where $X$ is a locally compact Hausdorff space, $\mathcal{B}$ a $\sigma$ -algebra that contains all compact subsets of $X$ and $\mu$ a measure such that:

  • $\mu(K) < \infty$ for all compact sets $K \subset X$ .
  • $\mu$ is inner regular, meaning $\mu(A) = \sup\{ \mu(K) : K \subset A, \; K\,{is compact}\}$
  • $\mu$ is outer regular, meaning $\mu(A) = \inf\{ \mu(U) : A \subset U,\; U \in \mathcal{B} {and}\; U\,{is open}\}$

We denote by $C_c(X)$ the space of continuous functions $X \to \mathbb{C}$ with compact support.

Theroem - For every $1 \leq p < \infty$ , $C_c(X)$ is dense in $L^p(X)$ .

Proof: It is clear that $C_c(X)$ is indeed contained in $L^p(X)$ , where we identify each function in $C_c(X)$ with its class in $L^p(X)$ .

We begin by proving that for each $A \in \mathcal{B}$ with finite measure, the characteristic function $\chi_A$ can be approximated, in the $L^p$ norm, by functions in $C_c(X)$ . Let $\epsilon > 0$ . By inner and outer regularity of $\mu$ , we know there exist an open set $U$ and a compact set $K$ such that $K \subset A \subset U$ and

$\displaystyle \mu(U \setminus K) = \mu(U) - \mu(K) < \epsilon$    

By the Urysohn's lemma for locally compact Hausdorff spaces, we know there is a function $f \in C_c(X)$ such that $0 \leq f \leq 1$ , $f|_K = 1$ and $\mathrm{supp}\,f \subset U$ . Hence,
$\displaystyle \int_X \vert\chi_A - f\vert^p \;d\mu = \int_{U \setminus K} \vert\chi_A - f\vert^p \;d\mu < \epsilon$    

Thus, $\chi_A$ can be approximated in $L^p$ by functions in $C_c(X)$ .

Now, it follows easily that any simple function $\sum_{i=1}^n c_i \chi_{A_i}$ , where each $A_i$ has finite measure, can also be approximated by a compactly supported continuous function. Since this kind of simple functions are dense in $L^p(X)$ we see that $C_c(X)$ is also dense in $L^p(X)$ . $\square$




Anyone with an account can edit this entry. Please help improve it!

"compactly supported continuous functions are dense in $L^p$" is owned by asteroid.
(view preamble | get metadata)

View style:

Other names:  $C_c(X)$ is dense in $L^p(X)$

This object's parent.
Log in to rate this entry.
(view current ratings)

Cross-references: simple function, open set, norm, characteristic function, finite, class, function, contained, clear, dense in, support, compact, continuous functions, outer regular, inner regular, compact sets, measure, compact subsets, contains, locally compact Hausdorff space, measure space

This is version 3 of compactly supported continuous functions are dense in $L^p$, born on 2008-12-26, modified 2008-12-26.
Object id is 11390, canonical name is CompactlySupportedContinuousFunctionsAreDenseInLp.
Accessed 769 times total.

Classification:
AMS MSC28C15 (Measure and integration :: Set functions and measures on spaces with additional structure :: Set functions and measures on topological spaces )
 46E30 (Functional analysis :: Linear function spaces and their duals :: Spaces of measurable functions ($L^p$-spaces, Orlicz spaces, Köthe function spaces, Lorentz spaces, rearrangement invariant)
 54C35 (General topology :: Maps and general types of spaces defined by maps :: Function spaces)

Pending Errata and Addenda
None.
Discussion
Style: Expand: Order:
forum policy

No messages.

Interact
post | correct | update request | prove | add result | add corollary | add example | add (any)