PlanetMath (more info)
 Math for the people, by the people. Sponsor PlanetMath
Encyclopedia | Requests | Forums | Docs | Wiki | Random | RSS  
Login
create new user
name:
pass:
forget your password?
Main Menu
Owner confidence rating: High Entry average rating: No information on entry rating
continuous epimorphism of compact groups preserves Haar measure (Theorem)

Theorem - Let $G, H$ be compact Hausdorff topological groups. If $\phi:G \longrightarrow H$ is a continuous surjective homomorphism, then $\phi$ is a measure preserving transformation, in the sense that it preserves the normalized Haar measure.

$\,$

Proof: Let $\mu$ be the Haar measure in $G$ (normalized, i.e. $\mu (G) = 1$ ). Let $\nu$ be defined for measurable subsets $E$ of $H$ by

$\displaystyle \nu(E)=\mu(\phi^{-1}(E)) $
It is easy to see that $\nu$ defines a measure in $H$ . Let us now see that $\nu$ is invariant under right translations. For every $s \in G$ and every measurable subset $E \subset H$ we have that
$\displaystyle \phi^{-1}(\phi(s)E)=s\phi^{-1}(E)$ (1)

The inclusion $\supseteq$ is obvious. To prove the other inclusion notice that if $z \in \phi^{-1}(\phi(s)E)$ then $\phi(z) = \phi(s)t$ for some $t \in E$ . Hence, $\phi(s^{-1}z)=t$ , i.e $s^{-1}z \in \phi^{-1}(E)$ . It now follows that $z=s(s^{-1}z) \in s\phi^{-1}(E)$ .

Thus, equality (1) and the fact that $\mu$ is a Haar measure imply that

$\displaystyle \nu(\phi(s)E)= \mu \big(\phi^{-1}(\phi(s)E)\big)=\mu(s\phi^{-1}(E)) = \mu(\phi^{-1}(E)) = \nu(E) $

Since $\phi$ is surjective it follows that $\nu$ is right invariant. It is not difficult to see that $\nu$ is regular, finite on compact sets and $\nu(H) = 1$ . Hence, $\nu$ is the normalized Haar measure in $H$ and, by definition, we have that

$\displaystyle \nu(E)=\mu(\phi^{-1}(E)) $
Thus, $\phi$ preserves the Haar measure. $\square$




Anyone with an account can edit this entry. Please help improve it!

"continuous epimorphism of compact groups preserves Haar measure" is owned by asteroid. [ full author list (2) ]
(view preamble | get metadata)

View style:

Log in to rate this entry.
(view current ratings)

Cross-references: compact sets, finite, regular, imply, equality, inclusion, translations, invariant, measure, easy to see, subsets, measurable, Haar measure, transformation, measure preserving, homomorphism, surjective, continuous, topological groups, Hausdorff, compact, theorem
There is 1 reference to this entry.

This is version 6 of continuous epimorphism of compact groups preserves Haar measure, born on 2008-04-10, modified 2009-01-02.
Object id is 10495, canonical name is ContinuousEpimorphismOfCompactGroupsPreservesHaarMeasure.
Accessed 728 times total.

Classification:
AMS MSC22C05 (Topological groups, Lie groups :: Compact groups)
 28C10 (Measure and integration :: Set functions and measures on spaces with additional structure :: Set functions and measures on topological groups, Haar measures, invariant measures)
 37A05 (Dynamical systems and ergodic theory :: Ergodic theory :: Measure-preserving transformations)

Pending Errata and Addenda
None.
[ View all 1 ]
Discussion
Style: Expand: Order:
forum policy

No messages.

Interact
post | correct | update request | prove | add result | add corollary | add example | add (any)