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ramification of archimedean places
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(Definition)
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Throughout this entry, if is a complex number, we denote the complex conjugate of by
.
Notice that any archimedean place
can be extended to an embedding
, where
is a fixed algebraic closure of
(in order to prove this, one uses the fact that
is algebraically closed and also Zorn's Lemma). See also this entry. In particular, if is a finite extension of then can be extended to an
archimidean place
of .
Next, we define the decomposition and inertia group associated to archimedean places. For the case of non-archimedean places (i.e. prime ideals) see the entries decomposition group and ramification.
Let be a finite Galois extension of number fields and let be a (real or a pair of complex) archimedean place of . Let and be two archimedean places of
which extend . Notice that, since is Galois, the image of and are equal, in other words:
Hence, the composition
is an automorphism of (here
denotes the inverse map of , restricted to ). Thus,
and
so and differ by an element of the Galois group. Similarly, if
and
are complex embeddings which extend , then there is
such that
meaning that either
(and thus
) or
(and thus
). We are ready now to make the definitions.
Definition 2 Let be a Galois extension of number fields and let be an archimedean place of lying above a place of . The decomposition and inertia subgroups for the pair are equal and are defined by:
Let
be the size of the inertia subgroup. If then we say that the archimedean place is ramified in the extension .
The ramification in the archimedean case is much simpler than the non-archimedean analogue. One readily proves the following proposition:
Proposition 1 The inertia subgroup is nontrivial only when is real,
is a complex archimedean place of and is the “complex conjugation” map which has order . Therefore or and ramification of archimedean places occurs if and only if there is a complex place of lying above
a real place of .
Proof. Suppose first that
 is a real embedding. Then  is injective and
implies that  is the identity automorphism and  would be trivial. So let us assume that
 is a complex archimedean place and let
 such that
Therefore, either
 (which implies that  is the identity by the injectivity of  ) or
 . The latter implies that
 , which is simply complex conjugation:
Finally, since  is an extension of  , the equation
 restricts to
 , thus  must be real. 
Corollary 1 Suppose is an extension of number fields and assume that is a totally imaginary number field. Then the extension is unramified at all archimedean places.
Proof. Since  is totally imaginary none of the embeddings of  are real. By the proposition, only real places can ramify. 
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"ramification of archimedean places" is owned by alozano.
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(view preamble)
Cross-references: imaginary, equation, complex conjugation, identity, implies, proposition, non-archimedean, archimedean, extension, size, subgroups, definitions, complex embeddings, Galois group, restricted, map, inverse, automorphism, composition, image, complex, real, Galois extension, ramification, decomposition group, inertia group, decomposition, finite extension, Zorn's lemma, algebraically closed, order, algebraic closure, fixed, ring of integers, prime ideals, place of field, embeddings, real embedding, number field, complex conjugate, complex number
There are 10 references to this entry.
This is version 6 of ramification of archimedean places, born on 2005-03-09, modified 2005-03-10.
Object id is 6861, canonical name is RamificationOfArchimedeanPlaces.
Accessed 4669 times total.
Classification:
| AMS MSC: | 11S15 (Number theory :: Algebraic number theory: local and $p$-adic fields :: Ramification and extension theory) | | | 13B02 (Commutative rings and algebras :: Ring extensions and related topics :: Extension theory) | | | 12F99 (Field theory and polynomials :: Field extensions :: Miscellaneous) |
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Pending Errata and Addenda
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